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77julia77 [94]
3 years ago
15

HELP PLEASE

Mathematics
1 answer:
vitfil [10]3 years ago
3 0
It’s 1 because of -8x^4-x^2+2
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IrinaVladis [17]

Answer:

Step-by-step explanation:

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6 0
2 years ago
The students at Midtown Middle school sold flowers as a fundraiser in September and October. In October, they charged $1.50 for
lions [1.4K]

In the question it is given that,

The students at Midtown Middle school sold flowers as a fundraiser in September and October. In October, they charged $1.50 for each flower

And the October price was a 20% increase of the September price.

Let the price of the flower in October be $x

So we have

x+  \frac{20}{100}x = 1.50 \\ \frac{120x}{100} = 1.50 \\ x = \frac{1.50*100}{120} = 1.25

So the price of the flower in Septembet is $1.25 .

7 0
3 years ago
Solve for b.<br><br> 3 (b−4 )+ 5b = 44<br><br><br> b =
Sergeu [11.5K]
B=7
3(b-4)+5b=44
3b-12+5b=44
8b=44+12
8b=56
b=7
7 0
3 years ago
The ratio of the heights of two similar prymaids is 3:2
Charra [1.4K]
What is the question?

4 0
3 years ago
Listed below are prices in dollars for one night at different hotels in a certain region. Find the​ range, variance, and standar
Artyom0805 [142]

Answer:

Range = 115$

Standard Deviation = 43.76$

Variance = 1915.142$

Option  A) The measures of variation are not very useful because when searching for a​ room, low​ prices, location, and good accommodations are more important than the amount of variation in the area.

Step-by-step explanation:

We are given the data for  prices in dollars for one night at different hotels in a certain region.

234, 160, 119, 131, 218, 207, 146, 141        

Range:

Sorted data: 119, 131, 141, 146, 160, 207, 218, 234

\text{Range} = 234-119 = 115\$

Standard Deviation:

\text{Standard Deviation} = \sqrt{\displaystyle\frac{\sum (x_i -\bar{x})^2}{n-1}}  

where x_i are data points, \bar{x} is the mean and n is the number of observations.  

Mean = \displaystyle\frac{\text{Sum of all observations}}{\text{Total number of observation}}

Mean =\displaystyle\frac{1356}{8} = 169.5

Sum of squares of differences = 4160.25 + 90.25 + 2550.25 + 1482.25 +  2352.25 + 1406.25 + 552.25 + 812.25 = 13406

\sigma = \sqrt{\dfrac{13406}{7}} = 43.76\$

Variance =

\sigma^2 = 1915.142\$

Measure of variance for someone searching for room:

Option  A) The measures of variation are not very useful because when searching for a​ room, low​ prices, location, and good accommodations are more important than the amount of variation in the area.

5 0
3 years ago
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