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stira [4]
3 years ago
9

In circle A shown below, the measure of ∠BAD is 148°: Circle A with angle BAD measuring 148 degrees; points B, C, D lie on Circl

e A. If m Arc BC is 96°, what is m Arc CD ?

Mathematics
1 answer:
german3 years ago
5 0

Answer:

52°

Step-by-step explanation:

In the figure attached, Circle A is shown. There we can see that:

∠BC + ∠CD =  ∠BAD

We know that Arc BC measures 96° and arc BAD measures 148°. Replacing this data into the equation and solving for Arc CD, we get:

96° + ∠CD =  148°

∠CD = 148° - 96°

∠CD = 52°

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goblinko [34]

Answer:

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Step-by-step explanation:

Let's recall that If the transversal cuts across parallel lines (apparently, this particular case) then those alternate exterior angles have the same measure (.∠ 110° and ∠?) So in the figure given, the two alternate exterior angles measure the same.

<u>The missing angle measures also 110°</u>

4 0
3 years ago
Emilia added 2 1⁄8 cups of brown sugar to the cookie dough and 1 2⁄8 cups of white sugar to the dough. How much more brown sugar
alexandr1967 [171]
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Find the Y-coordinate of point P that lies 1/3 along segment RS, where R (-7, -2) and S (2, 4).
QveST [7]

Solution:

Given that the point P lies 1/3 along the segment RS as shown below:

To find the y coordinate of the point P, since the point P lies on 1/3 along the segment RS, we have

\begin{gathered} RP:PS \\ \Rightarrow\frac{1}{3}:\frac{2}{3} \\ thus,\text{ we have} \\ 1:2 \end{gathered}

Using the section formula expressed as

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In this case,

\begin{gathered} m=1 \\ n=2 \end{gathered}

where

\begin{gathered} x_1=-7 \\ y_1=-2 \\ x_2=2 \\ y_2=4 \end{gathered}

Thus, by substitution, we have

\begin{gathered} [\frac{1(2)+2(-7)}{1+2},\frac{1(4)+2(-2)}{1+2}] \\ \Rightarrow[\frac{2-14}{3},\frac{4-4}{3}] \\ =[-4,\text{ 0\rbrack} \end{gathered}

Hence, the y-coordinate of the point P is

0

8 0
2 years ago
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x²+x+3x+3=0

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3 years ago
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LekaFEV [45]

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