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Ksenya-84 [330]
3 years ago
15

Use the quadratic formula to find both solutions to the quadratic equation given below. 4x^2+5x+1=0

Mathematics
2 answers:
fenix001 [56]3 years ago
6 0

Answer: B and D, you're welcome:3

RUDIKE [14]3 years ago
3 0
A and C. Those are the roots
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Describe how a point on a graph is related to a table and an equation that represent the same relationship.
castortr0y [4]

Answer:

because everything is relative to each other.

Step-by-step explanation: Graphing ordered pairs is only the beginning of the story. Once you know how to place points on a grid, you can use them to make sense of all kinds of mathematical relationships. A linear relationship is a relationship between variables such that when plotted on a coordinate plane, the points lie on a line. Let’s start by looking at a series of points in Quadrant I on the coordinate plane. Look at the five ordered pairs (and their x– and y-coordinates) below.

4 0
3 years ago
Read 2 more answers
What are the solutions to the equation
frosja888 [35]

Answer:

C.

x_1=\frac{1}{4}+(\frac{\sqrt{7}}{4})i and x_2=\frac{1}{4}-(\frac{\sqrt{7} }{4})i

Step-by-step explanation:

You have the quadratic function 2x^2-x+1=0 to find the solutions for this equation we are going to use Bhaskara's Formula.

For the quadratic functions ax^2+bx+c=0 with a\neq 0 the Bhaskara's Formula is:

x_1=\frac{-b+\sqrt{b^2-4.a.c} }{2.a}

x_2=\frac{-b-\sqrt{b^2-4.a.c} }{2.a}

It usually has two solutions.

Then we have  2x^2-x+1=0  where a=2, b=-1 and c=1. Applying the formula:

x_1=\frac{-b+\sqrt{b^2-4.a.c} }{2.a}\\\\x_1=\frac{-(-1)+\sqrt{(-1)^2-4.2.1} }{2.2}\\\\x_1=\frac{1+\sqrt{1-8} }{4}\\\\x_1=\frac{1+\sqrt{-7} }{4}\\\\x_1=\frac{1+\sqrt{(-1).7} }{4}\\x_1=\frac{1+\sqrt{-1}.\sqrt{7}}{4}

Observation: \sqrt{-1}=i

x_1=\frac{1+\sqrt{-1}.\sqrt{7}}{4}\\\\x_1=\frac{1+i.\sqrt{7}}{4}\\\\x_1=\frac{1}{4}+(\frac{\sqrt{7}}{4})i

And,

x_2=\frac{-b-\sqrt{b^2-4.a.c} }{2.a}\\\\x_2=\frac{-(-1)-\sqrt{(-1)^2-4.2.1} }{2.2}\\\\x_2=\frac{1-i.\sqrt{7} }{4}\\\\x_2=\frac{1}{4}-(\frac{\sqrt{7}}{4})i

Then the correct answer is option C.

x_1=\frac{1}{4}+(\frac{\sqrt{7}}{4})i and x_2=\frac{1}{4}-(\frac{\sqrt{7} }{4})i

3 0
2 years ago
Which conjunction is disjunction is equivalent to the given absolute value inequality? |x+2|<18
a_sh-v [17]

Answer:  conjunction and  -20<x <16 is answer.


Step-by-step explanation:

It is a conjunction because it is and statement

|x+2|<18 gives  

[Since  l x-a l <b means x-a lies between -b and b ]

-18<x+2<18

subtracting 2 in the whole  inequality ,we get

 -18-2 <x +2-2 < 18-2

   -20 < x < 16  

6 0
3 years ago
Which is a true statement?
Murrr4er [49]
A) -2.8 > -3.5 is true. There are infinite solutions.
B) -7.75 < -8.45 is false. There is no solution.
C) 6.52 < 6.5 is is false. There is no solution.
D) -11.1 > 10.7 is false. There is no solution.

3 0
3 years ago
Please answer fast!
asambeis [7]
Answer A

In^2 this multiplies the number used by itself therefore in your case 283 x 283. You are using the measurement for inches.
7 0
2 years ago
Read 2 more answers
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