How do I prove this problem?

Mathematics

1 answer:

vova2212 [387]3 years ago

4 0

I need to see the triangle

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Which product will be negative?

inysia [295]

Answer:

7x(-9)

Step-by-step explanation:

-3x-5 becomes positive 15

-2x-1 becomes positive 2

6x6 is 36

7x-9 is -63

5 0

2 years ago

Read 2 more answers

M is the midpoint of QR<br><br> M = (-2,6)<br> Q= (8,-10)<br> R = ????

Zolol [24]

Answer:

R = (-12, 22)

Step-by-step explanation:

Unfortunately it's not a straight line, so gonna need to put in some extra work. Basically think of it like breaking it into it's horizontal and vertical components then doubling them.

From Q to M you move 10 spaces to the left, so to go from M to R you will go another 10 to the left. Similarly, you start at -10 for the y value and go up 16 to 6, and you will need to go up another 16 to get to R.

So for x, 8 -10 = -2 then -2 - 10 = -12, so R's x value is -12

y we do the same thing. Gonna do it in one step though. -10 + 16 + 16 = 22

So R is (-12, 22)

4 0

2 years ago

May someone help me with this problem?

Katyanochek1 [597]

Answer:

$a. \: \: \frac{ {4x}^{6} }{ {y}^{3} } \\$

$b. \: \: \frac{ {8x}^{3} }{ {y}^{ 1\frac{1}{3} } } \\$

Step-by-step explanation:

${( {4x}^{ - 2} y)}^{ - 3} \\ {4x}^{ - 2 \times - 3} \: \: {y}^{1 \times - 3} \\ {4x}^{6} {y}^{ - 3} \\ \frac{ {4x}^{6} }{ {y}^{3} } \\$

${( {8x}^{6} {y}^{ - 3}) }^{ \frac{1}{2} } \\ {8x}^{6 \times \frac{1}{2} } \: \: {y}^{ - 3 \times \frac{1}{2} } \\ {8x}^{3} {y}^{ - \frac {3}{2} } \\ \frac{ {8x}^{3} }{ {y}^{ 1\frac{1}{3} } } \\$