Answer:
Choice D. 15.2%
Step-by-step explanation:
We have a normal...
mean u = 48
standard deviation s = 2
We want P(43 < X < 46)
We standardize.
Consider P(43 < X) = P( (43 - 48)/2 < Z) = P(-2.5 < Z)
P( X < 46) = P( Z < (46 - 48)/2 ) = P(Z < -1)
We want P( -2.5 < Z < -1)
Look at Z-scores.
P( Z < -2.5) = 0.0062
P(Z < -1) = 0.1587
so P(-2.5 < Z < -1) = P(Z < -1) - P(Z < -2.5) = 0.1587 - 0.0062 = 0.1525 = 15.2%
about
Since each vector is a member of

, the vectors will span

if they form a basis for

, which requires that they be linearly independent of one another.
To show this, you have to establish that the only linear combination of the three vectors

that gives the zero vector

occurs for scalars

.

Solving this, you'll find that

, so the vectors are indeed linearly independent, thus forming a basis for

and therefore they must span

.
-12+5
for -12.34,we take it as -12
for -4.8,we take it as -5
to measure the difference,here's what you need to do
-12-(-5)
=-12+5
thus the ans is -12+5
hope it helps
The first one is 9/25
The second one is 29.44
The last one is 8