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Zanzabum
3 years ago
14

The value in 3 in 300 is 30 times the value of 3 in?

Mathematics
2 answers:
Marysya12 [62]3 years ago
8 0
The value <span>of </span>3 in 300<span> is 10x</span><span> that of its </span>value<span> in </span>30 <span>not 1/10.</span>
Gala2k [10]3 years ago
6 0
The three in 300 is 10 times as great 10 times more
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Como medir la altura de un arbol usando el teorema de thales
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Step-by-step explanation:

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Can someone post an image of the "Cryptic Quiz 148" (OBJECTIVE 5-d: To solve an equation for y in terms of x.) "Why did the litt
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A lumber yard is the answer to that riddle.

Step-by-step explanation:

7 0
3 years ago
Barbara deposited $300 in the bank. If the bank pays her simple interest at the rate of 4 percent per year, how much money will
grigory [225]

Answer:

309

Step-by-step explanation:

The formula for simple interest is

A = P(1 + rt)

where A is the amount of money in the account

P is the principal invested

r is the interest rate in decimal form

t is the time invested in years

We know

P = 300

r = 4% = .04

t = 9 months = 9 months * 1 year/12 months = .75 year

Substituting into the equation

A = 300(1 + .04*.75)

  =300 (1+.03)

  =300(1.03)

   = 309

4 0
3 years ago
How many solutions does the equation sin(5x) = 1/2 have on the interval (0, 2PI]
Darina [25.2K]

Answer:

Step-by-step explanation:

Given the equation

Sin(5x) = ½

5x = arcSin(½)

5x = 30°

Then,

The general formula for sin is

5θ = n180 + (-1)ⁿθ

Divide through by 5

θ = n•36 + (-1)ⁿ30/5

θ = 36n + (-1)ⁿ6

The range of the solution is

0<θ<2π I.e 0<θ<360

First solution

When n = 0

θ = 36n + (-1)ⁿθ

θ = 0×36 + (-1)^0×6

θ = 6°

When n = 1

θ = 36n + (-1)ⁿ6

θ = 36-6

θ = 30°

When n = 2

θ = 36n + (-1)ⁿ6

θ = 36×2 + 6

θ = 78°

When n =3

θ = 36n + (-1)ⁿ6

θ = 36×3 - 6

θ = 102°

When n=4

θ = 36n + (-1)ⁿ6

θ = 36×4 + 6

θ = 150

When n =5

θ = 36n + (-1)ⁿ6

θ = 36×5 - 6

θ = 174°

When n = 6

θ = 36n+ (-1)ⁿ6

θ = 36×6 + 6

θ = 222°

When n = 7

θ = 36n + (-1)ⁿ6

θ = 36×7 - 6

θ = 246°

When n =8

θ = 36n + (-1)ⁿ6

θ = 36×8 + 6

θ = 294°

When n =9

θ = 36n + (-1)ⁿ6

θ = 36×9 - 6

θ = 318°

When n =10

θ = 36n + (-1)ⁿ6

θ = 36×10 + 6

θ = 366°

When n = 10 is out of range of θ

Then, the solution is from n =0 to n=9

So the equation have 10 solutions in the range 0<θ<2π

4 0
3 years ago
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