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Pie
3 years ago
15

9/4 - 17/6= ?Can someone please help me?​

Mathematics
1 answer:
Ostrovityanka [42]3 years ago
7 0

Answer:

-0.58333333333

Step-by-step explanation:

Find the Least Common Multiple

     The left denominator is :       4

     The right denominator is :       6

       Number of times each prime factor

       appears in the factorization of:

Prime

Factor   Left

Denominator   Right

Denominator   L.C.M = Max

{Left,Right}

2 2 1 2

3 0 1 1

Product of all

Prime Factors  4 6 12

Least Common Multiple:

    12

Calculate multipliers for the two fractions

   Denote the Least Common Multiple by  L.C.M

   Denote the Left Multiplier by  Left_M

   Denote the Right Multiplier by  Right_M

   Denote the Left Denominator by  L_Deno

   Denote the Right Multiplier by  R_Deno

  Left_M = L.C.M / L_Deno = 3

  Right_M = L.C.M / R_Deno = 2

Rewrite the two fractions into equivalent fractions

Two fractions are called equivalent if they have the same numeric value.

For example :  1/2   and  2/4  are equivalent,  y/(y+1)2   and  (y2+y)/(y+1)3  are equivalent as well.

To calculate equivalent fraction, multiply the Numerator of each fraction, by its respective Multiplier.

  L. Mult. • L. Num.      9 • 3

  ——————————————————  =   —————

        L.C.M              12  

  R. Mult. • R. Num.      17 • 2

  ——————————————————  =   ——————

        L.C.M               12  

Adding up the two equivalent fractions

Add the two equivalent fractions which now have a common denominator

Combine the numerators together, put the sum or difference over the common denominator then reduce to lowest terms if possible:

9 • 3 - (17 • 2)      -7

—————— =   ——

       12                 12

\frac{-7}{12} = -0.58333333333

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Can someone help please????​
egoroff_w [7]
Y= 80.55% approximately, 80.6% rounded up

Calculations:

The percent (percentage) of a given number p/q can be found, for the most part, without a calculator by a slight change in the notation:

y=the number 29/36 expressed as a percent becomes

y=[29(2.7777777778 approx.)]/[36(2.7777777778 approx.)]

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y=0.8055(100)

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3 years ago
Determine the equations of the vertical and horizontal asymptotes, if any, for y=x^3/(x-2)^4
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Answer:

Option a)

Step-by-step explanation:

To get the vertical asymptotes of the function f(x) you must find the limit when x tends k of f(x). If this limit tends to infinity then x = k is a vertical asymptote of the function.

\lim_{x\to\\2}\frac{x^3}{(x-2)^4} \\\\\\lim_{x\to\\2}\frac{2^3}{(2-2)^4}\\\\\lim_{x\to\\2}\frac{2^3}{(0)^4} = \infty

Then. x = 2 it's a vertical asintota.

To obtain the horizontal asymptote of the function take the following limit:

\lim_{x \to \infty}\frac{x^3}{(x-2)^4}

if \lim_{x \to \infty}\frac{x^3}{(x-2)^4} = b then y = b is horizontal asymptote

Then:

\lim_{x \to \infty}\frac{x^3}{(x-2)^4} \\\\\\lim_{x \to \infty}\frac{1}{(\infty)} = 0

Therefore y = 0 is a horizontal asymptote of f(x).

Then the correct answer is the option a) x = 2, y = 0

3 0
4 years ago
Read 2 more answers
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Answer:

The roots of the equation are x=-3 and x=-2.5

Step-by-step explanation:

<u><em>The correct quadratic equation is</em></u>

2x^2+11x+15=0

we know that

The formula to solve a quadratic equation of the form

ax^{2} +bx+c=0 is equal to

x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}

in this problem we have

2x^{2} +11x+15=0  

so

a=2\\b=11\\c=15

substitute in the formula

x=\frac{-11(+/-)\sqrt{11^{2}-4(2)(15)}} {2(2)}

x=\frac{-11(+/-)\sqrt{121-120}} {4}

x=\frac{-11(+/-)\sqrt{1}} {4}

x=\frac{-11(+/-)1} {4}

x_1=\frac{-11(+)1}{4}=-2.5

x_2=\frac{-11(-)1}{4}=-3

therefore

The roots of the equation are x=-3 and x=-2.5

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