(6k+2)-(3k-2)
expand brackets 18k²-12k+6k-4
simplify 18k²-6k-4
Answer:
53.1 degrees
Step-by-step explanation:
use sohcahtoa
sin(x) = 12/15
sin(x) = 0.8
sin-1(0.8) = 53.1301
Answer:
=8b + 5
Step-by-step explanation:
do you need an explantion
Suppose the larger pump alone can empty the tank in L hours, and the smaller pump can finish the job in S hours, then each hour the large pump empties 1/L portion of the tank, and the small pump empties 1/S per hour
Working together for three hours, they empty the whole tank, which is 100% of it, so 3/L+3/S=100%=1
Larger pump can empty the tank in 4 hours less than the smaller one, so L=S-4
replace L: 3/(S-4)+3/S=1
Make the denominator the same to solve for:
3S/[S(S-4)] +3(S-4)/[S(S-4)]=1
(3S+3S-12)/[S(S-4)]=1
(3S+3S-12)=[S(S-4)]
S^2-10s+12=0
use the quadratic formula to solve for S
S is about 8.6
The answer is not whole hour.
Answer:
y = 3x + 13
Step-by-step explanation:
Here, we want to solve for y
To solve for y, we simply are going to make y the subject of the formula
We have this as;
y - 3x = 13
y = 13 + 3x
