Question

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Answer 1

Answer:

The correct option is 1. The axis of symmetry of the given graph is x=1.

Step-by-step explanation:

If a quadratic function is defined as

$y=ax^2+bx+c$              ... (1)

then, the axis of symmetry is

$x=-\frac{b}{2a}$

The given parabolic equation is

$y=2x^2-4x+4$             .... (2)

On comparing (1) and (2), we get

$a=2,b=-4,c=4$

The axis of symmetry of given graph is

$x=-\frac{(-4)}{2(2)}$

$x=-\frac{(-4)}{4}$

$x=1$

Therefore the axis of symmetry of the given graph is x=1 and option 1 is correct.