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Ipatiy [6.2K]
3 years ago
6

What is the area of a regular pentagon with 7 inch sides and an apothem of 3.9 inches?

Mathematics
1 answer:
Marrrta [24]3 years ago
8 0
A(n)=(ns^2)/(4tan(180/n)) in this case:

a=(5*49)/(4tan36)

a=84.3in^2
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The diagram shows a logo made from three circles
Nana76 [90]

Answer:

3cm+2cm+5cm=10cm

%=100

10*10=100

2cm*10=20%

Step-by-step explanation:

the shaded area is width of 2 2/10 or 20/100

8 0
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Christie needs 54.3 Square feet of laminate wood suppose each square foot of laminated wood cost $.60 find the amount she has to
Irina18 [472]
It will cost $33.

Since wood cost $ .60 sq ft, you can assume she needs to buy 55 sq ft because she will need to buy enough to have 54.3 square ft.

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2 years ago
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X = -230/3 hope that helps
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2 years ago
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Leslie used 20% of a half-gallon (64 ounces) of milk for a recipe. How many ounces of milk were left?
Lady_Fox [76]

Answer:

51.2 ounces.

Step-by-step explanation:

If its 20% of a 64 ounce half gallon, you just need to find the last 80% of the half gallon. Since you know it is 64 ounces you can divide it by 5 which gives you 12.8. 12.8 would be 20% so you just subtract 12.8 from 64 ounces which gives you 51.2.

5 0
2 years ago
A probability model includes P(red) = 27 2 7 and P(blue) = 314 3 14 . Which of the following probabilities could complete the mo
Ivahew [28]

Answer:

(b)\ P(Green) = \frac{3}{8} ; P(Yellow) = \frac{1}{8}

(c)\ P(Green) = \frac{1}{4} ; P(Yellow) = \frac{1}{4}

Step-by-step explanation:

Given

P(Red) = \frac{2}{7}

P(Blue) = \frac{3}{14}

Required

Which completes the model

Let the remaining probability be x.

Such that:

P(Red) +  P(Blue) + x = 1

Make x the subject

x = 1 - P(Red) - P(Blue)

So, we have:

x = 1 - \frac{2}{7} - \frac{3}{14}

Solve

x = \frac{14 - 4 - 3}{14}

x = \frac{7}{14}

x = \frac{1}{2}

This mean that the remaining model must add up to 1/2

(a)\ P(Green) = \frac{2}{7} ; P(Yellow) = \frac{2}{7}

P(Green) + P(Yellow)= \frac{2}{7} + \frac{2}{7}

Take LCM

P(Green) + P(Yellow)= \frac{2+2}{7}

P(Green) + P(Yellow)= \frac{4}{7}

This is false because: \frac{4}{7} \ne \frac{1}{2}

(b)\ P(Green) = \frac{3}{8} ; P(Yellow) = \frac{1}{8}

P(Green) + P(Yellow)= \frac{3}{8} + \frac{1}{8}

Take LCM

P(Green) + P(Yellow)= \frac{3+1}{8}

P(Green) + P(Yellow)= \frac{4}{8}

P(Green) + P(Yellow)= \frac{1}{2}

This is true

(c)\ P(Green) = \frac{1}{4} ; P(Yellow) = \frac{1}{4}

P(Green) + P(Yellow)= \frac{1}{4} + \frac{1}{4}

Take LCM

P(Green) + P(Yellow)= \frac{1+1}{4}

P(Green) + P(Yellow)= \frac{2}{4}

P(Green) + P(Yellow)= \frac{1}{2}

This is true

Other options are also false

6 0
3 years ago
Read 2 more answers
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