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Leno4ka [110]
3 years ago
9

The diagram shows a logo made from three circles

Mathematics
2 answers:
Nana76 [90]3 years ago
8 0

Answer:

3cm+2cm+5cm=10cm

%=100

10*10=100

2cm*10=20%

Step-by-step explanation:

the shaded area is width of 2 2/10 or 20/100

professor190 [17]3 years ago
3 0

Answer:

below

Step-by-step explanation:

Radius of the middle circle = 7 cm

Radius of the inner circle = 4 cm

the area of the biggest circle is= π10² = 100πcm²

the area of the medium circle is= π7² = 49πcm²

the area of the smallest circle is= π5² = 25πcm²

Area of the inner circle = π(4)²= 16π

Area of the shaded region= 49π - 16π = 33π

% area of the shaded region =  33%

Therefore, area of the shaded region is 33% of the complete logo.

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2 + 3(3x - 6) = 5(x - 3) + 15 I'm in Algebra 1 and I still can't seem to get this problem, I use Slader to find how to do this b
Wewaii [24]

Answer:

x = 4

Step-by-step explanation:

2 + 3(3x - 6) = 5(x - 3) + 15

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2 + 9x - 18 = 5x - 15 + 15

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9x - 16 = 5x

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4x - 16 = 0

Add 16 to both sides:

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7 0
3 years ago
Find the domain of the function y = 3 tan(23x)
solmaris [256]

Answer:

\mathbb{R} \backslash \displaystyle \left\lbrace \left. \frac{1}{23}\, \left(k\, \pi + \frac{\pi}{2}\right)  \; \right| k \in \mathbb{Z}  \right\rbrace.

In other words, the x in f(x) = 3\, \tan(23\, x) could be any real number as long as x \ne \displaystyle \frac{1}{23}\, \left(k\, \pi + \frac{\pi}{2}\right) for all integer k (including negative integers.)

Step-by-step explanation:

The tangent function y = \tan(x) has a real value for real inputs x as long as the input x \ne \displaystyle k\, \pi + \frac{\pi}{2} for all integer k.

Hence, the domain of the original tangent function is \mathbb{R} \backslash \displaystyle \left\lbrace \left. \left(k\, \pi + \frac{\pi}{2}\right)  \; \right| k \in \mathbb{Z}  \right\rbrace.

On the other hand, in the function f(x) = 3\, \tan(23\, x), the input to the tangent function is replaced with (23\, x).

The transformed tangent function \tan(23\, x) would have a real value as long as its input (23\, x) ensures that 23\, x\ne \displaystyle k\, \pi + \frac{\pi}{2} for all integer k.

In other words, \tan(23\, x) would have a real value as long as x\ne \displaystyle \frac{1}{23} \, \left(k\, \pi + \frac{\pi}{2}\right).

Accordingly, the domain of f(x) = 3\, \tan(23\, x) would be \mathbb{R} \backslash \displaystyle \left\lbrace \left. \frac{1}{23}\, \left(k\, \pi + \frac{\pi}{2}\right)  \; \right| k \in \mathbb{Z}  \right\rbrace.

4 0
3 years ago
I need help ON THIS PLS
Anit [1.1K]

Answer:

No, because the ratio of pay to hours is not the same for each pair of value.

8 0
3 years ago
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gregori [183]
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3 years ago
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Kay [80]

Answer:

a) 3x⁴-4x³-8x²-35x-10

Step-by-step explanation:

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5 0
2 years ago
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