Answer:
The difference in slopes of 
is = 3
We can say slope of 
is positive and 3 more than slope of 
while slope of is negative.
Difference of y-intercepts of is = -7
We can say the y-intercept of is positive and 7 units above while y-intercept of is negative.
Step-by-step explanation:
Given equation:
We need to find the difference of slopes and y-intercepts of the given equations.
The standard form of a slope intercept equation of line is given by:
where 
represents slope and 
represents y-intercept of line.
Writing the given equations in standard form to find slope and y-intercept.
Slope = 2 and y-intercept =-2
Slope = -1 and y-intercept =5
The difference in slopes of is = 
We can say slope of is positive and 3 more than slope of while slope of is negative.
Difference of y-intercepts of is = 
We can say the y-intercept of is positive and 7 units above while y-intercept of is negative.
I assume you mean 5/8 of a pound not 58 pounds. In that case convert your total number of pounds into eights to make it easier to calculate. 5 pounds is equal to 40/8 pounds of cheese. Now divide this by 5/8. That equals 8. SO you can make 8 batches.
Answer: 
Step-by-step explanation:
The average speed of the car is 40 miles per hour:
The car drives for 45 minutes:
Since 1 hours has 60 minutes, we can convert the time from minutes to hours:
Knowing these values, we can use the following formula for calculate the distace "d":
Therefore, substituting values into the formula, we get:
Answer:
4/6 is more than 5/12
Step-by-step explanation:
First, set the denominators of the fractions equal to eachother to make it easier to compare. mulitiply 6 and 4 by 2 so that the denominator now equals 12, and you have the new fractions 5/12 and 8/12. Since 8/12 is more than 5/12, 4/6 is more than 5/12.
Answer: 0.31
Step-by-step explanation:
Let A denotes the event that the students report drinking alcohol and B denotes the students report using some type of tobacco product .
Given : P(A) =0.84 ; P(B)=0.33 and P(A∪B)=0.86
We know that 
Then, the probability that the student both drunk alcohol and used tobacco in the past month is given by :-
Hence, the probability that the student both drunk alcohol and used tobacco in the past month = 0.31
