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schepotkina [342]
3 years ago
8

Which graph depicts the path of a projectile​

Mathematics
2 answers:
xz_007 [3.2K]3 years ago
6 0
<h2>B is the answer</h2><h2 />

Step-by-step explanation:

Alekssandra [29.7K]3 years ago
3 0

Step-by-step explanation:

When an object is thrown at an angle with horizontal under the action of gravity is called projectile motion and the object which is thrown is called a projectile. The path followed by the object is parabolic. An object when thrown in upward direction, after reaching maximum height it will come back to ground.

Graph (b) shows the path of a projectile.

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Will give brainlest if correct, and 5 stars.<br><br> Solve for x
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Answer:

x = 54

Step-by-step explanation:

These angles are complementary because they add up to 90:

x - 7 + 43 = 90

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Find the area of a regular pentagon with an apothem of 6 inches and a side length of 8.7 inches. Round to the nearest tenth.
Lapatulllka [165]
  1. The area of the pentagon is 130.5 inches. The area of a pentagon, if you don’t know, is equal to the perimeter of the pentagon times the apothem, all divided by 2. Because one side of the pentagon has a length of 8.7 inches, and all sides of a pentagon have the same length, then the perimeter would be equivalent to 8.7 times 5, which equals a perimeter of 43.5 inches. Now that our perimeter is found, our equation is set (because the apothem is 6 inches, as said in the problem). Now, to solve, we have to multiply the perimeter (43.5 in.) by the apothem (6 in.), which equals 261 inches. Now, all we have to do is divide it by 2, which will give us our answer of 130.5 inches. Bonus: The answer only reaches out to one decimal point, meaning that there is no need to round!
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See attached question
Nady [450]

Answer:

Its 34 times 87

Step-by-step explanation:

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Show all steps!!!
Lunna [17]
-\frac{1}{3}\left|1\cdot \left(\frac{1}{2}\right)^2\right|-\frac{2}{3}-2^3-\frac{2}{3}\left|-\frac{1}{2}\right|^3
\frac{1}{3}\left|1\cdot \left(\frac{1}{2}\right)^2\right|=\frac{1}{12}
\frac{2}{3}\left|-\frac{1}{2}\right|^3=\frac{1}{12}
=-\frac{1}{12}-\frac{2}{3}-2^3-\frac{1}{12}
=-\frac{53}{6}
4 0
4 years ago
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