If I'm understanding the question correctly, this is how I would estimate the sum.
I would round each number to the nearest tens place.
33 would be rounded down to 30.
89 would be rounded up to 90.
Then I would do 90+30.
Answer:
$1444
Step-by-step explanation:
7% of 9200 = 644
644 + 800 = 1444
:)
Answer: 0.8461
Step-by-step explanation:
Given : 
Let x be the random variable that represents the cost for the hospital emergency room visit.
We assume that cost for the hospital emergency room visit is normally distributed .
z-score for x=1000 ,
Using z-value table , we have
P-value =P(x>1000)=P(z>-1.02)=1-P(z≤ -1.02)=1-0.1538642
=0.8461358≈0.8461 [Rounded nearest 4 decimal places]
Hence, the probability that the cost will be more than $1000 = 0.8461
A=4
B=0
C=7
X=16
This is what I think