The intersecting secant theorem states the relationship between the two intersecting secants of the same circle. The given problems can be solved using the intersecting secant theorem.
<h3>What is Intersecting Secant Theorem?</h3>
When two line secants of a circle intersect each other outside the circle, the circle divides the secants into two segments such that the product of the outside segment and the length of the secant are equal to the product of the outside segment other secant and its length.
a(a+b)=c(c+d)
1.)
6(x+6) = 5(5+x+3)
6x + 36 = 25 + 5x + 15
x = 4
2.)
4(2x+4)=5(5+x)
8x + 16 = 25 + 5x
3x = 9
x = 3
3.)
8x(6x+8x) = 7(9+7)
8x(14x) = 112
112x² = 112
x = 1
4.)
(x+3)² = 16(x-3)
x² + 9 + 6x = 16x - 48
x² - 10x - 57 = 0
x = 14.0554
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Answer:
The answer would be 26
Step-by-step explanation:
First I divided the shape to make a rectangle and a right angle triangle, then i calculated the shape of the rectangle which came out to be 20. After that I calculated the area of the right angle triangle which is 6. So The answer would be 6 + 20 = 26
Area of a rectangle: A = 24 a² b
Length: L = 8 a b²
Width: W = A / L = 24 a² b / 8 a b²
Answer: W = 3 a / b
Answer:
60
Step-by-step explanation:
area of triangle ACF is (1/2) (AC) (CF) = 180
area of triangle BCE = (1/2) (BC) (CE)
BC = AC/2
CE=(2/3) CF
so (1/2) (BC) (CE) = (1/2) (AC/2) (2/3)CF = (1/2)(2/3)(180) = 60 sq cm
Xt-3=y
Move three to the other side as a positive number
xt=3+y
Divide everything by x
t=3+y divided by x
