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3 years ago

The values of x and y vary directly, and when x=48, y=36. Find the value of x when y=18.

Mathematics

1 answer:

Karo-lina-s [1.5K]3 years ago

4 0

Answer:

Step-by-step explanation:

48 ÷ 2 = 24 - x

36 ÷ 2 = 18 - y

x = 24

y = 18

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Find the discriminant and determine the nature of the roots to the quadratic equation

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№17
$x^{2} +6x-7=0 \\ D=6 ^{2} -4*(-7)=36+28=64=8 ^{2} \\ \\ x_{1} = \frac{-6+8}{2} =1 \\ \\ x_{2} = \frac{-6-8}{2} =-7$
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$2 x^{2} -3x+4=3 \\ 2 x^{2} -3x+4-3=0 \\ 2 x^{2} -3x+1=0 \\ \\ D= -3 ^{2} -4*2=9-8=1 \\ \\ x_{1} = \frac{3+1}{2*2} = \frac{4}{4} =1 \\ \\ x_{2} = \frac{3-1}{2*2} = \frac{2}{4} =0.5$
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№19
$2 x^{2} -4x-5=0 \\ D=-4 ^{2} -4*2*(-5)=16+40=56 \\ \\ x_{1}= \frac{4+ \sqrt{56} }{2*2} = \frac{4}{4} + \sqrt{ \frac{56}{16} } =1+ \sqrt{3.5} \\ \\ x_{2} = \frac{4- \sqrt{56} }{2*2} = \frac{4}{4} - \sqrt{ \frac{56}{16} } =1- \sqrt{3.5} 
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4 years ago

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3 years ago

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Mashcka [7]

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B). The hypothesis is: a quadrilateral having exactly one pair of parallel opposite sides.

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Step-by-step explanation:

I just did the assignment on Edge. It's 100% correct!! Hope this helps!!

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4 years ago