I believe the GCF would be 2n
Answer:
0.018 is the probability that a randomly selected college student has an IQ greater than 131.5
Step-by-step explanation:
We are given the following information in the question:
Mean, μ = 100
Standard Deviation, σ = 15
We are given that the distribution of IQ score is a bell shaped distribution that is a normal distribution.
Formula:
a) P(IQ greater than 131.5)
P(x > 131.5)
Calculation the value from standard normal z table, we have,
0.018 is the probability that a randomly selected adult has an IQ greater than 131.5
Answer: 3
Step-by-step explanation:
Vertical angles are made by two intersecting lines .and they are always equal
<span>∠C and ∠D are equal.
so </span><span>−x+26 =2x-10
-3x=-36
x=36/3
x=12</span>°
∠D= 2x-10
put value of x here
∠D=24-10
∠D=14°
