The two positive numbers whose difference is 9 and whose product is 2950 are 50 and 59
<h3>How to determine the positive numbers?</h3>
As a general rule, it should be noted that positive numbers are numbers that have their value greater than 0
So, we start by representing the two positive numbers with x and y.
So, we have the following equations
x - y = 9
xy = 2950
Make x the subject in the first equation x - y = 9
x = y + 9
Substitute y + 9 for x in the second equation
(y + 9) * y = 2950
Expand the equation
y^2 + 9y - 2950 = 0
Using a graphing tool, we have the solution of the above equation to be
y = 50
Recall that:
x = 9 + y
So, we have:
x = 9 + 50
Evaluate
x = 59
Hence, the two positive numbers whose difference is 9 and whose product is 2950 are 50 and 59
Read more about positive numbers at:
brainly.com/question/1782403
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So this is a two step process, first you must find the area of the rectangle, then find the area of the semicircle.
So to find the area of a rectangle, you use: Length*Height=Area
In this case that would be: 7*2=14cm
Next you find the area of the semicircle, to do this you first find the area of the circle (Pi*r^2) then divide it by 2.
The diameter of the circle is 4 because: 7-2-1=4cm
Next divide that by 2 so that you get the radius: 4/2=2cm
Not you can plug that into the equation to get the area of the circle: Pi*2^2<span>≈13cm^2
Next divide it by 2 so that you get the area of the semicircle:13/2</span><span><span>≈</span>6cm^2
At this point you can add the area of the semicircle to the area of the rectangle: 14+6=20cm^2
So your final answer is 20cm^2!
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= 98 2/3
= 98 + 2/3
= 98/1 + 2/3
= (98/1 * 3/3) + 2/3
= 294/3 + 2/3
= 296/3
= 296 ÷ 3
= 98.666667
