The question is shown below. Please help me answer!

7,243 ÷ 4.<br><br> What is the remainder?

Sveta_85 [38]

Divested using long division
1810 r 3

4 0

3 years ago

Of the 800 participants in a marathon 220 are running to raise money for a cause. How many participants out of 100 are running f

nadezda [96]

Answer:

27.5 /100 are running for a cause

Step-by-step explanation:

We know that 220/800 are running for a cause

Divide the top and bottom by 8 to get the fraction out of 100

220 /8 =27.5

800/8 = 100

27.5 /100 are running for a cause

7 0

2 years ago

The scores on the GMAT entrance exam at an MBA program in the Central Valley of California are normally distributed with a mean

Kaylis [27]

Answer:

58.32% probability that a randomly selected application will report a GMAT score of less than 600

93.51% probability that a sample of 50 randomly selected applications will report an average GMAT score of less than 600

98.38% probability that a sample of 100 randomly selected applications will report an average GMAT score of less than 600

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this problem, we have that:

$\mu = 591, \sigma = 42$

What is the probability that a randomly selected application will report a GMAT score of less than 600?

This is the pvalue of Z when X = 600. So

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{600 - 591}{42}$

$Z = 0.21$

$Z = 0.21$ has a pvalue of 0.5832

58.32% probability that a randomly selected application will report a GMAT score of less than 600

What is the probability that a sample of 50 randomly selected applications will report an average GMAT score of less than 600?

Now we have $n = 50, s = \frac{42}{\sqrt{50}} = 5.94$

This is the pvalue of Z when X = 600. So

$Z = \frac{X - \mu}{s}$

$Z = \frac{600 - 591}{5.94}$

$Z = 1.515$

$Z = 1.515$ has a pvalue of 0.9351

93.51% probability that a sample of 50 randomly selected applications will report an average GMAT score of less than 600

What is the probability that a sample of 100 randomly selected applications will report an average GMAT score of less than 600?

Now we have $n = 50, s = \frac{42}{\sqrt{100}} = 4.2$

$Z = \frac{X - \mu}{s}$

$Z = \frac{600 - 591}{4.2}$

$Z = 2.14$

$Z = 2.14$ has a pvalue of 0.9838

98.38% probability that a sample of 100 randomly selected applications will report an average GMAT score of less than 600

8 0

3 years ago

Carly and janiya put some money into their money boxes every week. the amounts of money (y), in dollars, in their money boxes af

Lelu [443]

Carly : y = 60x + 40
janiya : y = 50x + 80

60x + 40 = 50x + 80
60x - 50x = 80 - 40
10x = 40
x = 40/10
x = 4 <=== so at 4 weeks, they will have the same amount of money <==
The money they have is : y = 60(4) + 40.....y = $ 280 <=

so ur answer is : 4 weeks, $ 280

8 0

2 years ago

A. A farmer irrigates her fields with 120,000 cubic yards of water. She has a 1,000-acre farm. How

horsena [70]

Answer:

120 cc yards of water

Step-by-step explanation:

A farmer has 1,000-acre farm. And she irrigates her fields with 120,000 cubic yards of water. We are asked to find how many cubic feet of water does she apply per acre?

1000 acre is irrigated by = 120000 cc yard of water

Hence 1 Acre is irrigated by

$= \frac{120000}{1000}$ cc yards of water

Hence 1 Acre is irrigated by 120 cc yards of water .

8 0

2 years ago