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Elena-2011 [213]
2 years ago
15

Find two positive numbers whose difference is 9 and whose product is 2950.

Mathematics
1 answer:
Naddika [18.5K]2 years ago
5 0

The two positive numbers whose difference is 9 and whose product is 2950 are 50 and 59

<h3>How to determine the positive numbers?</h3>

As a general rule, it should be noted that positive numbers are numbers that have their value greater than 0

So, we start by representing the two positive numbers with x and y.

So, we have the following equations

x - y = 9

xy = 2950

Make x the subject in the first equation x - y = 9

x = y + 9

Substitute y + 9 for x in the second equation

(y + 9) * y = 2950

Expand the equation

y^2 + 9y - 2950 = 0

Using a graphing tool, we  have the solution of the above equation to be

y = 50

Recall that:

x = 9 + y

So, we have:

x = 9 + 50

Evaluate

x = 59

Hence, the two positive numbers whose difference is 9 and whose product is 2950 are 50 and 59

Read more about positive numbers at:

brainly.com/question/1782403

#SPJ1

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Answer:

• David

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• 4 miles

Explanation:

In the graph:

The given locations are:

• Owen's House, A(11,3)

,

• David's House, B(15,13)

,

• School, C(3,18)

We determine both Owen's and David's distance from the school using the distance formula.

Distance=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Owen's distance from school (AC)

\begin{gathered} AC=\sqrt[]{(3-11)^2+(18-3)^2} \\ =\sqrt[]{(-8)^2+(15)^2} \\ =\sqrt[]{64+225} \\ =\sqrt[]{289} \\ AC=17\text{ miles} \end{gathered}

David's distance from school (BC)

\begin{gathered} BC=\sqrt[]{(3-15)^2+(18-13)^2} \\ =\sqrt[]{(-12)^2+(5)^2} \\ =\sqrt[]{144+25} \\ =\sqrt[]{169} \\ BC=13\text{ miles} \end{gathered}

We see from the calculations that David lives closer to the school, and by 4 miles.

The graph below is attached for further understanding:

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1 year ago
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Solve #1 pls, I need to find the shortest side, median side, and longest side
Lisa [10]

Answer:

Shortest side = 39 cm.

Median side = 65 cm.

Longest side = 91 cm.

Step-by-step explanation:

The perimeter in total is 195 cm. The ratio of the sides are 3 : 5 : 7.

First, find how much parts there are as a whole, by combining the ratios:

3 + 5 + 7 = 15 parts.

Divide the total of parts from the total measurement:

195/15 = 13

Each part has the measurement of 13 cm.

1 part = 13 cm.

Use the following ratio to solve for each of the sides:

Shortest side: 3

3 x 13 = 39

Shortest side = 39 cm.

Median side: 5

5 x 13 = 65

Median side = 65 cm.

Longest side: 7

7 x 13 = 91

Longest side = 91 cm.

Check. Combine all side measurements together. They should equal 195:

39 + 65 + 91 = 195

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7) 13 in. Because the hypotenuse is the longest length than opposite and adjacent.

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