Question

(I need the answer right now please) ΔA'B'C' was constructed using ΔABC and line segment EH. 2 triangles are shown. Line E H is the line of reflection. Line segment B B prime has a midpoint at point D. Line segment A A prime has a midpoint at point F. Line segment C C prime has a midpoint at point G. For to be the line of reflection between and , which statements must be true? Select three options. BD = DB' DF = FG m∠EFA = 90° The line of reflection, EH, is the perpendicular bisector of BB', AA', and CC'. ΔABC is not congruent to ΔA'B'C'.

Answer 1

Answer:

A

Step-by-step explanation:

Answer 2

Answer:

The true statements are

1. BD = DB'

3. m∠EFA = 90°

4. The line of reflection, EH, is the perpendicular bisector of BB', AA', and

   CC'

Step-by-step explanation:

* Lets explain how to solve the problem

- Reflection is flipping an object over the line of reflection.

- The object and its image have the same shape and size, but the

  figures are in opposite directions from the line of reflection

- The objects appear as if they are mirror reflections, with right and left

  reversed

- The line of reflection is a perpendicular bisector for all lines joining

  points on the figure with their corresponding images

- Look to the attached figure for more understand

* Lets solve the problem

- ΔA'B'C' was constructed using ΔABC and line segment EH, where

 EH is the reflection line

- D is the mid-point of BB'

- F is the mid-point of AA'

- G is the mid-point of CC'

* Lets find from the answer the true statements

1. BD = DB'

∵ D is the mid point of BB'

- Point D divides BB' into two equal parts

∴ BD = DB' ⇒ True

2. DF = FG

- It depends on the size of the sides and angles of the triangle

∵ We can't prove that

∴ DF = FG ⇒ Not true

3. m∠EFA = 90°

∵ The line of reflection ⊥ the lines joining the points with their

   corresponding images

∴ EH ⊥ AA' and bisect it at F

∴ m∠EFA = 90° ⇒ True

4. The line of reflection, EH, is the perpendicular bisector of BB',

   AA', and CC'

- Yes the line of reflection is perpendicular bisectors of them

∴ The line of reflection, EH, is the perpendicular bisector of BB',

   AA', and CC' ⇒ True

5. ΔABC is not congruent to ΔA'B'C'

∵ In reflection the object and its image have the same shape and size

∴ Δ ABC is congruent to Δ A'B'C'

∴ ΔABC is not congruent to ΔA'B'C' ⇒ Not true