What is the smallest number which has a reminder of 2 when it is divided by 6,7 and 8
1 answer:
170 is the smallest number which has a reminder of 2 when it is divided by 6,7 and 8
<u>Step-by-step explanation:</u>
The Least or Lowest Common Multiple (LCM) or Least Common Divisor (LCD).
For two integers a and b, denoted LCM (a, b), the LCM is the smallest positive integer that is evenly divisible by both a and b. The LCM of two or more numbers is the smallest number that is evenly divisible by all numbers in the set. Let find LCM of 6, 7 and 8.
We add 2 to LCM to get the smallest number which gives a remainder of 2.
So, the number is 168+ 2 = 170
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5) So for parallelogram ABCD, ∠B ≅ ∠D, and ∠A ≅ ∠C. Further, ∠B and ∠A are supplementary (i.e., their sum is 180°), and ∠D and ∠C are also supplementary.
So, we have that m∠B = m∠D. Therefore,
Now, let's substitute for x back into the expression for either ∠B or ∠D to find it's angle measure.
m∠B =
Now, remember that ∠B or ∠D are supplements of ∠A.
So, m∠B + m∠A = 180°.
That means m∠A = 180° – 72° = 108°.
That seems reasonable, because A appears to be an obtuse angle.
So, we have that m∠B = m∠D. Therefore,
Now, let's substitute for x back into the expression for either ∠B or ∠D to find it's angle measure.
m∠B =
Now, remember that ∠B or ∠D are supplements of ∠A.
So, m∠B + m∠A = 180°.
That means m∠A = 180° – 72° = 108°.
That seems reasonable, because A appears to be an obtuse angle.
Answer:
yd^2
Step-by-step explanation:
Formula:
p = 7.5 + 7.5 = 15
q = 13 + 13 = 26
A = 195