Answer:
![\rule[225]{225}{2}](https://tex.z-dn.net/?f=%5Crule%5B225%5D%7B225%7D%7B2%7D)
Step-by-step explanation:
We can find the slope through two points.
m = (y2 - y1)/(x2 - x1)
m = (4 - -5)/(4 - -8)
m = 9/12 = 3/4
The slope of the line is 3/4.
Slope-intercept form of a line is y=mx+b. Where m is the slope and b is the y-intercept.
y = 3/4x + b
A point on the line is (4, 4). x = 4 and y =4.
4 = 3/4(4) + b
4 = 3 + b
b = 1
The y-intercept is 1.
Answer:
D. The plane needs to be about 27 meters higher to clear the tower.
Step-by-step explanation:
In this scenario a triangle is being formed. The base the plane's takeoff point to the tower base which is 42 meters (x).
The hypothenus is the distance travelled by the plane which is 83 meters (h)
The height of the tower is 98 Meters
We want to calculate the height of our triangle (y) so we can guage if the plane scaled the tower.
According to Pythagorean theorem
(x^2) + (y^2) = h^2
y = √ (h^2) - (x^2)
y = √ (83^2) - (42^2)
y= √(6889 - 1764)
y= 71.59 Meters
The height from the plane's position to the top of the tower will be
Height difference = 98 - 71.59 = 26.41 Meters
So the plane should go about 27 Meters higher to clear the tower
Answer and Step-by-step explanation:
Given that if a polygon is a square, then a polygon is a quadrilateral, we find the converse, inverse and contrapositive of this implicational statement. The hypothesis is the causative statement and the conclusion is the resultant effect
The converse of this statement is the reverse of its statements hence:
If a polygon is a quadrilateral then a polygon is a square
The inverse of this statement is the negation of the statements hence :
If a polygon is not a square then a polygon is not a quadrilateral
The contrapositive of the statement is the interchange of the hypothesis and conclusion of the inverse statement hence:
If a polygon is not a quadrilateral then a polygon is not a square
Answer:
Step-by-step explanation:
side of square=10+10+20=40 m
area of square=40×40=1600 m²
area of small square=π10²=100 π m²
area of bigger semi circle=1/2 ×π×20²=200 π m²
reqd. area of shaded region=1600-(100π+200π)=1600-300π m²
≈1600-300×3.14
≈1600-942
≈658 m²
