Question

The area of a rectangle is 52ft square, and the length of the rectangle is 5 ft less than twice the width. Find the dimensions of the rectangle.

Answer 1

Given: A= 52ft² and l= 2w-5
know that formula for A= lw, substitute for what you know and solve for w
52=(2w-5)w -> w= -4, w=6.5 but because a width measurement can not be negative, you can eliminate w=-4. so the width is equal to 6.5ft
now input that in the equation for length and solve for l:
l=2w-5=2(6.5)-5=8 
so the length is 8 ft