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andreev551 [17]
2 years ago
12

Please answer as quickly as you can! ♥ Find two possible dimensions for a cylinder that has a volume of 64π cm³.

Mathematics
1 answer:
11Alexandr11 [23.1K]2 years ago
3 0

Answer:

Possible dimensions are r=4\,\,cm\,,\,h=4\,\,cm and h=16\,\,cm\,,\,r=2\,\,cm

Step-by-step explanation:

Given:

Volume of a cylinder is 64\pi\,\,cm^3

To find: Dimensions of a cylinder

Solution:

Let r,h denote height of a cylinder.

Volume of a cylinder = \pi r^2h

Therefore,

64\pi=\pi r^2h\\64=r^2h\\4^2\,4=r^2h

One possible dimension can be r=4\,\,cm\,,\,h=4\,\,cm.

Also, 64=r^2h can be written as 16(2^2)=hr^2

So, another possible dimension can be h=16\,\,cm\,,\,r=2\,\,cm

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A professor pays 25 cents for each blackboard error made in lecture to the student who pointsout the error. In a career ofnyears
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Answer:

(a) The probability that <em>Y</em>₂₀ exceeds 1000  is 3.91 × 10⁻⁶.

(b) <em>n</em> = 28.09

Step-by-step explanation:

The random variable <em>Y</em>ₙ is defined as the total numbers of dollars paid in <em>n</em> years.

It is provided that <em>Y</em>ₙ can be approximated by a Gaussian distribution, also known as Normal distribution.

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(a)

For <em>n</em> = 20 the mean and standard deviation of <em>Y</em>₂₀ are:

\mu_{Y_{n}}=40n=40\times20=800\\\sigma_{Y_{n}}=\sqrt{100n}=\sqrt{100\times20}=44.72\\

Compute the probability that <em>Y</em>₂₀ exceeds 1000 as follows:

P(Y_{n}>1000)=P(\frac{Y_{n}-\mu_{Y_{n}}}{\sigma_{Y_{n}}}>\frac{1000-800}{44.72})\\=P(Z>  4.47)\\=1-P(Z

**Use a <em>z </em>table for probability.

Thus, the probability that <em>Y</em>₂₀ exceeds 1000  is 3.91 × 10⁻⁶.

(b)

It is provided that P (<em>Y</em>ₙ > 1000) > 0.99.

P(Y_{n}>1000)=0.99\\1-P(Y_{n}

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Compute the value of <em>n</em> as follows:

z=\frac{Y_{n}-\mu_{Y_{n}}}{\sigma_{Y_{n}}}\\2.33=\frac{1000-40n}{\sqrt{100n}}\\2.33=\frac{100}{\sqrt{n}}-4\sqrt{n}  \\2.33=\frac{100-4n}{\sqrt{n}} \\5.4289=\frac{(100-4n)^{2}}{n}\\5.4289=\frac{10000+16n^{2}-800n}{n}\\5.4289n=10000+16n^{2}-800n\\16n^{2}-805.4289n+10000=0

The last equation is a quadratic equation.

The roots of a quadratic equation are:

n=\frac{-b\pm\sqrt{b^{2}-4ac}}{2a}

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Find the point of diminishing returns (x comma y )for the function​ R(x), where​ R(x) represents revenue​ (in thousands of​ doll
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Complete Question

The complete question is shown on the first uploaded image  

Answer:

The point of diminishing returns (x , y ) is  (11, 21462)

Step-by-step explanation:

From the question we are told that

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Here R(x)  represents revenue (in thousands of​ dollars) and  x  represents the amount spent on advertising​ (in thousands of​ dollars).

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Finding the second derivative of R(x)

              R''(x) =  -6x +66

at  inflection point    R''(x) =  0

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=>           x=  11

    substituting value of x into R(x)

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Now the point of diminishing returns (x , y ) i.e (x , R(x) ) is

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