Given :
C, D, and E are col-linear, CE = 15.8 centimetres, and DE= 3.5 centimetres.
To Find :
Two possible lengths for CD.
Solution :
Their are two cases :
1)
When D is in between C and E .
. . .
C D E
Here, CD = CE - DE
CD = 15.8 - 3.5 cm
CD = 12.3 cm
2)
When E is in between D and C.
. . .
D E C
Here, CD = CE + DE
CD = 15.8 + 3.5 cm
CD = 19.3 cm
Hence, this is the required solution.
Answer:
y=79/73x+644/73
theres the equation, enjoy <3
Step-by-step explanation:
x=14-6y/3
substituting x=14-6y/3 into eqn 2
2(14-6y/3)+8y=2
multiplying through by 3
2(14-6y/3)×3 +8y×3=2×3
2(14-6y)+24y=6
28-12y+24y=6
28-12y=6
28-6=12y
22=12y
22/12=y
finding x
2x+8(22/12)=2
2x+44/3=2
2x=2-44/3
x=(-38/3)/2
×=-38/6
Answer:
Step 1 should be (14.4+18)...PEMDAS
Step-by-step explanation:
Studs is the answer to this question.
Vertical structural members are called Studs. This is the term which is used in construction. There are exterior and interior walls which are framed, these walls are known as bearing walls, and some are also non- bearing. Whenever there is foundation in a place, after the first floor deck these bearing walls are formed.
