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Vesnalui [34]
3 years ago
11

Does this graph represent a function? Why or why not?

Mathematics
1 answer:
Snezhnost [94]3 years ago
3 0

Answer:

B

Step-by-step explanation:

it is not a function because it fails the vertical line test,

A vertical line intersect the graph no more than once.

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PLZ help me super really really fast
maria [59]

Answer:

A. 3 cm

Step-by-step explanation:

The smallest face has the sides 4 cm and 8 cm. If the water is 4 cm from its top, then the height of the water is 16-4=12 cm and the volume of the water is

V_{water}=4\cdot 8\cdot 12=384\ cm^3

The largest face has the sides 8 cm and 16 cm. If the container is placed on its largest face, then the volume of the water is

V_{water}=8\cdot 16\cdot h \ cm^3,

where h is the height of the water.

Equate volumes of the water:

8\cdot 16\cdot h=384\\ \\h=\dfrac{384}{8\cdot 16}=3\ cm

Therefore, the water is 3 cm from the bottom.

4 0
3 years ago
(17 Leon uses 3/4 cup water to make a serving of iced tea.
Ksivusya [100]

Answer:

A.) 12 3/4 cups

B.) 117 1/3

Step-by-step explanation:

<u>Part A</u>

If one serving of ice tea contains 3/4 cup of water, how much does 7 serving have?

To answer this, you must multiply 3/4 and 17

17 is the same as 17/1, so multiply the numerators and denominators

17 x 3 = 51

1 x 4 = 4

51/4 = 12 3/4

So, Leon used 51/4 or 12 3/4 cups of water

<u>Part B</u>

If the cooler has 88 servings of tea, how many cups of water does it have?

To solve this, divide 88 by 3/4

Dividing 88 by 3/4 is the same as multiplying 88 by 4/3.

Again, 88 is the same as 88/1 so multiply the numerators and the denominators.

88 x 4 = 352

1 x 3 = 3

352/3 = 117 1/3

So, there are 352/3 or 117 1/3 cups of water in the cooler

I hope this helps!

4 0
3 years ago
Please help thank you.
Wittaler [7]
30 60 90 right triangle
leg = 6 so other leg = 6√3

A = (1/2)(6+6)( 6√3+ 6√3)
A = 6 (12√3)
A = 72√3

answer is D
72√3

7 0
3 years ago
A projectile is fired with muzzle speed 250 m/s and an angle of elevation 45° from a position 30 m above ground level. Where doe
qaws [65]

The projectile's horizontal and vertical positions at time t are given by

x=\left(250\dfrac{\rm m}{\rm s}\right)\cos45^\circ\,t

y=30\,\mathrm m+\left(250\dfrac{\rm m}{\rm s}\right)\sin45^\circ\,t-\dfrac g2t^2

where g=9.8\dfrac{\rm m}{\mathrm s^2}. Solve y=0 for the time t it takes for the projectile to reach the ground:

30+\dfrac{250}{\sqrt2}t-4.9t^2=0\implies t\approx36.2458\,\mathrm s

In this time, the projectile will have traveled horizontally a distance of

x=\dfrac{250\frac{\rm m}{\rm s}}{\sqrt2}(36.2458\,\mathrm s)\approx6400\,\mathrm m

The projectile's horizontal and vertical velocities are given by

v_x=\left(250\dfrac{\rm m}{\rm s}\right)\cos45^\circ

v_y=\left(250\dfrac{\rm m}{\rm s}\right)\sin45^\circ-gt

At the time the projectile hits the ground, its velocity vector has horizontal component approx. 176.77 m/s and vertical component approx. -178.43 m/s, which corresponds to a speed of about \sqrt{176.77^2+(-178.43)^2}\dfrac{\rm m}{\rm s}\approx250\dfrac{\rm m}{\rm s}.

7 0
3 years ago
Pls help me with A, B, C, D
AlekseyPX

Use PEMDAS with the first 3.

a. 3×(6÷5)

3×(1.2) [Parenthesis first]

3.6. [then multiply]

b. 3÷(5×6)

3÷(30) [Parenthesis first]

.1 [then divide]

c. (3×6)÷5

(18)÷5 [Parenthesis first]

3.6 [then divide]

d. 3×6÷5

18÷5 [Left to right]

3.6 [then divide]

8 0
3 years ago
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