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Yuri [45]
3 years ago
9

Rewrite the quadratic function in vertex form. Y=3x^2-12x+4

Mathematics
1 answer:
Karolina [17]3 years ago
5 0

Answer:

vertex form is y=a(x−h)2+k. To solve this you have to complete the square with the x terms: y= 3x2−12x+4. first isolate the x terms: y−4=3x2−12x. ax2+bx+c to complete the square a=1 and c=(12b)2.

Step-by-step explanation:

vertex form is y=a(x−h)2+k. To solve this you have to complete the square with the x terms: y= 3x2−12x+4. first isolate the x terms: y−4=3x2−12x. ax2+bx+c to complete the square a=1 and c=(12b)2.

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At a strawberry stand Luisa paid $4.50 for 2 pounds of strawberries. How much would you expect to pay for five pounds or strawbe
Daniel [21]

<u>Half</u> of 4.50 is 2.25, so for <u>one</u> pound it would be <u>$2.25</u>.

To calculate five pounds, you need to add 2.25+2.25+2.25+2.25+2.25 = <u>11.25</u>.

For <u>five</u> pounds of strawberry's, it would cost <u>$11.25</u>.

Hope this helped !

4 0
3 years ago
Read 2 more answers
Which one of the quotients is correct? A) 876 ÷ 43 = 20r17B) 876 ÷ 43 = 20r16C) 876 ÷ 43 = 20r7D) 876 ÷ 43 = 20r6
Olegator [25]

To check which of the quotients is correct, multiply 43 times 20 and add the remainder. The result must be equal to 876.

First, notice that 20 times 43 equals 860.

A)

The remainder is 17. 860 + 17 = 877, which is not equal to 876.

B)

The remainder is 16. 860 + 16 = 876, which is equal to 876.

C)

The remander is 7. 860 + 7 = 867, which is not equal to 876.

D)

The remainder is 6. 860 + 6 = 866, which is not equal to 876.

Since 20*43 + 16 = 876, then the correct quotient is shown in option B:

876 ÷ 43 = 20 r 16

4 0
1 year ago
Finding interior angles of triangles<br>​
AnnZ [28]

Answer:

A triangle is 180 degrees. Imagine that two angles would be given as maybe 89 and 30 degrees. With these two angles already given you can find the last third angle by adding the 2 given angles and subtracting it from 180. There fore it would look like 180-119=61. 61 would be your unknown angle degree.

<u>If you meant something else please comment I will help you more.</u>

7 0
2 years ago
Heron’s formula: Area = square root 5(5-a)(5-b)(5-c) What is the area of triangle DFG? Round to the nearest whole square unit. 2
timurjin [86]
To do this problem, you will need to know the side lengths of the triangle. If you have those, just plug them in for a, b, and c and evaluate the square root.

Here is an example. If the sides are 3, 4, 5.
It would be:

A= \sqrt{6(6-3)(6-4)(6-5))}

The 6 is in the formula because it is the semi-perimeter (half).
3 0
3 years ago
Read 2 more answers
In this problem, x = c1 cos t + c2 sin t is a two-parameter family of solutions of the second-order DE x'' + x = 0. Find a solut
Norma-Jean [14]

Differentiate the given solution:

x=C_1\cos(t)+C_2\sin(t) \implies x'=-C_1\sin(t)+C_2\cos(t)

Now, given that <em>x</em> (<em>π</em>/4) = √2/2 … (I'm assuming there are symbols missing somewhere) … you have

\dfrac{\sqrt2}2=C_1\cos\left(\dfrac\pi4\right)+C_2\sin\left(\dfrac\pi4\right)

\implies\dfrac1{\sqrt2} = \dfrac{C_1}{\sqrt2}+\dfrac{C_2}{\sqrt2}

\implies C_1+C_2=1

Similarly, given that <em>x'</em> (<em>p</em>/4) = 0, you have

0=-C_1\sin\left(\dfrac\pi4\right)+C_2\cos\left(\dfrac\pi4\right)

\implies 0=-\dfrac{C_1}{\sqrt2}+\dfrac{C_2}{\sqrt2}

\implies C_1=C_2

From this result, it follows that

C_1+C_2=2C_1=1 \implies C_1=C_2=\dfrac12

So the particular solution to the DE that satisfies the given conditions is

\boxed{x=\dfrac12\cos(t)+\dfrac12\sin(t)}

7 0
2 years ago
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