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Alla [95]
3 years ago
14

How can you find and use absolute value? I can find absolute value by...

Mathematics
1 answer:
Tamiku [17]3 years ago
5 0

Answer:

Step-by-step explanation: Step 1: Isolate the absolute value expression.

Step2: Set the quantity inside the absolute value notation equal to + and - the quantity on the other side of the equation.

Step 3: Solve for the unknown in both equations.

Step 4: Check your answer analytically or graphically.

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NEED HELP ASAP!!! WILL GIVE BRAINLIEST!!!
Olin [163]

Answer:

  (6, 6)

Step-by-step explanation:

Each grid square is 2 units. 10 units up from point P is 5 grid squares up, or 3 grid squares above the x-axis. The x-coordinate remains the same (6), and the y-coordinate is the one labeling the 3rd line above the x-axis: 6.

The coordinates of point S are (6, 6).

5 0
3 years ago
Solve the equation p/4+10=14
Gelneren [198K]

Answer:

p=16

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
A humer four-door costs the dealer $57,915 the deaer has a 12.3% makeup
UNO [17]

Answer:

65038.55

Step-by-step explanation:

First, Let's turn 12.3% into a decimal which is 0.123

Then Multiply 57,915 by 0.123

57,915 × 0.123= 7123.545 Round; 7,123.55

Then Add  [Mark up = Add] 57,915 with 7,123.55

57,915 + 7,123.55= 65038.55

Hence, the Answer is 65038.55

4 0
2 years ago
At the zoo, 129 female spiders laid a total of 337,851 eggs. If each female spider laid the same amount of eggs, how many did ea
victus00 [196]

Answer:

43,582,779

Step-by-step explanation:

129 x 337,851 = 43,582,779

8 0
3 years ago
Read 2 more answers
A university interested in tracking its honors program believes that the proportion of graduates with a GPA of 3.00 or below is
insens350 [35]

Answer:

The value of the test statistic and its associated p-value at the 5% significance level are -1.54 and 0.9382, respectively.

Step-by-step explanation:

A university interested in tracking its honors program believes that the proportion of graduates with a GPA of 3.00 or below is less than 0.16.

This means that the null hypothesis is:

H_{0}: p \geq 0.16

Testing this hypothesis, means that the alternate hypothesis is:

H_{a}: p > 0.16

The test statistic is:

z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}

In which X is the sample mean, \mu is the value tested at the null hypothesis, \sigma is the standard deviation and n is the size of the sample.

0.16 is tested at the null hypothesis:

This means that \mu = 0.16, \sigma = \sqrt{0.16*0.84}

In a sample of 200 graduates, 24 students have a GPA of 3.00 or below.

This means that n = 200, X = \frac{24}{200} = 0.12

Value of the test statistic:

z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}

z = \frac{0.12 - 0.16}{\frac{\sqrt{0.16*0.84}}{\sqrt{200}}}

z = -1.54

Pvalue:

The pvalue is the probability of finding a sample mean above 0.12, which is 1 subtracted by the pvalue of z = -1.54.

Looking at the z-table, z = -1.54 has a pvalue of 0.0618

1 - 0.0618 = 0.9382

The value of the test statistic and its associated p-value at the 5% significance level are -1.54 and 0.9382, respectively.

6 0
3 years ago
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