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mixas84 [53]
3 years ago
9

The median of the set {0, 0, 4, 6, 6, 8} is

Mathematics
2 answers:
alukav5142 [94]3 years ago
4 0
A is the answer for the question
Scorpion4ik [409]3 years ago
3 0
Its not a its 4 iknow this bc were doing this
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What is the stem-and-leaf plot for
Verdich [7]

The stem-and-leaf plot for 29,22,21,6,13,6,17,29,26,9,16,10,25,3,2,23,13,10,7,16,29,30,4,11,7,28,27,22,10 is shown in the image attached below (see attachment).

<h3>What is a Stem-and-leaf Plot?</h3>

A stem-and-leaf plot is a table which is used to display a set of data in such a way that, on the left we have the "stem" which displays the first digit or digits of a data value.

On the right, we have the 'leaf' which displays the last digit of the data value.

For example, if we are to represent "25" and "26" on a stem-and-leaf plot, we would have: 2 | 5, 6.

Therefore, the stem-and-leaf plot for 29,22,21,6,13,6,17,29,26,9,16,10,25,3,2,23,13,10,7,16,29,30,4,11,7,28,27,22,10 is shown in the image attached below (see attachment).

Learn more about the stem-and-leaf plot on:

brainly.com/question/8649311

8 0
2 years ago
PLEASE HELP FIRST ONE GETS IT
Anna [14]

Answer:x=-1

Step-by-step explanation:

To solve 6-3+4x+1=

Collect like terms

6+1-3+4x=

7-3+4x=

4=-4x

x=-1

There is one solution

5 0
3 years ago
Please solve this question​
oee [108]

Answer:

\frac{1}{81}

Step-by-step explanation:

Using the rule of exponents

a^{-m} ⇔ \frac{1}{a^{m} }

Evaluating from the inside parenthesis outwards

(-\frac{1}{3}) ^{2} = - \frac{1}{3} × - \frac{1}{3} = \frac{1}{9} , then

(\frac{1}{9}) ^{-2} = \frac{1}{9^{-2} } = 9² = 81 , then

(81)^{-1} = \frac{1}{81}

4 0
2 years ago
Given two people earning $10/hour, one person earning $15/hour, and two people earning $20/hour, what is the median pay rate bei
yulyashka [42]
I think it would be $15/hour
5 0
3 years ago
Who wants to be the brainliest? Rearrange the formula C = 2πr for r.
faltersainse [42]

Answer:

B) r= c/2\pi

Step-by-step explanation:

To isolate r, divide 2\pi on both sides

c = 2\pir

--     --

2\pi   2\pi

c/2\pi=r

Hope this helps! :)

8 0
2 years ago
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