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aleksley [76]
3 years ago
10

HElP mE wItH tHiS pLeAsE

Mathematics
1 answer:
kvv77 [185]3 years ago
3 0

Answer:

1. n = -3.2

2. n = - 5

3. n = -0.2

4. n = - 32

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Consider the picture attached.

From right triangle trigonometry: 

tan(α)=(opposite side)/(adjacent side)=15/67=0.2239

using a scientific calculator we find that arctan(0.2239)=12.62°

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The angle made with the + y-axis is 12.62°+90°=102.62°.



The length of the vector v can be determined using the Pythagorean theorem:

|v|= \sqrt{ 67^{2} + 15^{2} }= \sqrt{4489+225}= \sqrt{4714}=68.8


Thus, to make v a unit vector, without changing its direction, we need to divide v by |v|=68.8. 

This means that the x and y components will also be divided by 68.8, by proportionality.

So, the unit vector in the direction of v is:

<span>(67/68.8)i + (-15/68.8)j=0.97 i + (- 0.22)j
</span>

Answer: 12.62°;  102.62°;  0.97 i + (- 0.22)j

6 0
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Let's move like a crab, backwards some.

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after 3 years?

\bf ~~~~~~ \textit{Compound Interest Earned Amount}&#10;\\\\&#10;A=P\left(1+\frac{r}{n}\right)^{nt}&#10;\quad &#10;\begin{cases}&#10;A=\textit{accumulated amount}\\&#10;P=\textit{original amount deposited}\to &\$1000\\&#10;r=rate\to 3\%\to \frac{3}{100}\to &0.03\\&#10;n=&#10;\begin{array}{llll}&#10;\textit{times it compounds per year}\\&#10;\textit{annually, thus once}&#10;\end{array}\to &1\\&#10;t=years\to &3&#10;\end{cases}&#10;\\\\\\&#10;A=1000\left(1+\frac{0.03}{1}\right)^{1\cdot 3}\implies A=1000(1.03)^3

is that enough to pay the $1100?


now, let's write 1000(1+r)² in standard form

1000( 1² + 2r + r²)

1000(1 + 2r + r²)

1000 + 2000r + 1000r²

1000r² + 2000r + 1000   <---- standard form.
8 0
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