N= 15
M= 15 √ 3
Brainliest please
The answer to this question is A
2

Suggesting that you want this in standard form, in terms of quadratic equations, you would technically follow a process similar if not almost exactly like the 2 - step equation method with the exception of separating the (x)s and the equations to find x and then plug it in and what-not.
With that being said you would subtract 5 in (x+5) from said 5 in the second equation and -10 in the first equation in order to get 2x^2+7x-15, you would continue to do the same for the x by subtracting it from both ends making the 7x a 6x because there is a 1 at the beginning of each x if there is no number that is shown already. Which finally gives you the equation (y= 2x^2+6x-15)
Given that the terminal side of an <θ intersects the unit circle at the point
![P(\frac{5}{6},\frac{-\sqrt[]{11}}{6})](https://tex.z-dn.net/?f=P%28%5Cfrac%7B5%7D%7B6%7D%2C%5Cfrac%7B-%5Csqrt%5B%5D%7B11%7D%7D%7B6%7D%29)
From the given point P:
![\begin{gathered} x=\frac{5}{6} \\ y=\frac{-\sqrt[]{11}}{6} \\ \text{ s}ince,\text{ x is positive and y is negative, the angle lies in the 4th quadrant} \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20x%3D%5Cfrac%7B5%7D%7B6%7D%20%5C%5C%20y%3D%5Cfrac%7B-%5Csqrt%5B%5D%7B11%7D%7D%7B6%7D%20%5C%5C%20%5Ctext%7B%20s%7Dince%2C%5Ctext%7B%20x%20is%20positive%20and%20y%20is%20negative%2C%20the%20angle%20lies%20in%20the%204th%20quadrant%7D%20%5Cend%7Bgathered%7D)