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Inessa [10]
4 years ago
10

Question 1 of 10

Mathematics
1 answer:
Zanzabum4 years ago
8 0

Answer:

A: 40 degrees

Step-by-step explanation:

Since every triangle is 180 degrees, you can start off by subtracting 50 from 180 since that side does not contain a y for you to solve.

Since the other two sides do have a y in them, you would set 130 degrees equal to y+10 and 2y:

130=y+10+2y

Then you would isolate the y's by subtracting 10, and you would add y and 2y together to get:

120=3y

Finally, you would divide 120 by 3 to get your answer, 40=y.

Hope this helps!

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4(x-5)=10(x-10)<br><br> solve for x
Zina [86]

Answer:

40/3

Step-by-step explanation:

4x -20 = 10x -100 (Distributive Property)

4x -10x = -100 +20 (I swith the numbers so all of them are similar)

-6x= -80 (Divide -6 on both sides)

And you will get 40/3 or 13.3333..

7 0
3 years ago
Elysia added -218+(-395) and got a sum of -613.Which best explains whether or not Elysia sum is reasonable?​
Thepotemich [5.8K]

Answer:

I don't know your options, but it is reasonable.

Step-by-step explanation:

Adding a negative is equivalent to subtracting a positive, so you would get

-218-395

=-613

7 0
4 years ago
In a factory, the chance that a certain machine works without overheating in the morning is 50%. if it runs smoothly all morning
Degger [83]

Answer: C. 7.5%

Solve as decimal

0.5*0.15=0.075

Move two decimal points over

0.075 -> 7.5

Change back to percent

7.5%

3 0
2 years ago
Question
Kay [80]

Answer:

f(x)=2(x-2)(x^2+64)

Step-by-step explanation:

A standard polynomial in factored form is given by:

f(x)=a(x-p)(x-q)...

Where <em>p</em> and <em>q</em> are the zeros.

We want to find a third-degree polynomial with zeros <em>x</em> = 2 and <em>x </em>= -8i and equals 320 when <em>x </em>= 4.

First, by the Complex Root Theorem, if <em>x</em> = -8i is a root, then <em>x </em>= 8i must also be a root.

Therefore, we acquire:

f(x)=a(x-(2))(x-(-8i))(x-(8i))

Simplify:

f(x)=a(x-2)(x+8i)(x-8i)

Expand the second and third factors:

=(x+8i)x+(x+8i)(-8i)\\\\=(x^2+8ix)+(-8ix-64i^2)\\\\=(x^2)+(8ix-8ix)+(-64i^2)\\\\=x^2-64(-1)\\\\ =x^2+64

Hence, our function is now:

f(x)=a(x-2)(x^2+64)

It equals 320 when <em>x</em> = 4. Therefore:

320=a(4-2)(4^2+64)

Solve for <em>a</em>. Evaluate:

320=(2)(80)a

So:

320=160a\Rightarrow a=2

Our third-degree polynomial equation is:

f(x)=2(x-2)(x^2+64)

7 0
3 years ago
Picture below need answer fast
IRINA_888 [86]
Ok can you help me with this 137x8 multiply with expanded form please???? I will help with yours
7 0
3 years ago
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