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Scorpion4ik [409]
2 years ago
8

From the above histogram find out which age group teachers are most in the school​

Mathematics
1 answer:
Anna35 [415]2 years ago
6 0
You need to provide the above histogram.
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Satellite dishes are shaped like parabolas to optimally revive signals. The cross section of a satellite dish can be modeled by
Anna11 [10]

The cross section of the satellite dish is an illustration of a quadratic function

The quadratic function that models the cross-section is y = 1/6(x^2 - 9)

<h3>How to determie the equation of the cross-section?</h3>

The given parameters are:

Width = 6 feet

Depth = 1.5 feet

Express the width the sum of two equal numbers

Width = 3 + 3

The above means that, the equation of the cross section passes through the x-axis at:

x = -3 and 3

So, we have:

y = a(x - 3) * (x + 3)

Express as the difference of two squares

y = a(x^2 - 9)

The depth is 1.5.

This is represented as: (x,y) =(0,-1.5)

So, we have:

-1.5 = a(0^2 - 9)

Evaluate the exponent

-1.5 = -9a

Divide both sides by -9

a = 1/6

Substitute 1/6 for a in y = a(x^2 - 9)

y = 1/6(x^2 - 9)

Hence, the quadratic function that models the cross-section is y = 1/6(x^2 - 9)

Read more about quadratic functions at:

brainly.com/question/1497716

7 0
2 years ago
Which amount of money is possible for Katie to spend for pens and notebooks?
Degger [83]

Answer:

the answer the B

Step-by-step explanation:

4 0
2 years ago
Read 2 more answers
The lengths of lumber a machine cuts are normally distributed with a mean of 106 inches and a standard deviation of 0.3 inch. ​(
Vinvika [58]

Answer:

a) P(X>106.11)=P(\frac{X-\mu}{\sigma}\frac{106.11-106}{0.3})=P(z>0.37)

And we can find this probability with the complement rule:

P(z>0.37)=1-P(z

b) z =\frac{106.11- 106}{\frac{0.3}{\sqrt{44}}}=  2.431

And if we use the z score we got:

P(z>2.431) =1-P(z

Step-by-step explanation:

Let X the random variable that represent the lengths of a population, and for this case we know the distribution for X is given by:

X \sim N(106,0.3)  

Where \mu=106 and \sigma=0.3

Part a

We are interested on this probability

P(X>106.11)

And we can use the z score formula given by:

z=\frac{x-\mu}{\sigma}

And using this formula we got:

P(X>106.11)=P(\frac{X-\mu}{\sigma}\frac{106.11-106}{0.3})=P(z>0.37)

And we can find this probability with the complement rule:

P(z>0.37)=1-P(z

Part b

For this case we select a sample of n =44 and the new z score formula is given by:

z=\frac{x-\mu}{\frac{\sigma}{\sqrt{n}}}

And if we find the z score we got:

z =\frac{106.11- 106}{\frac{0.3}{\sqrt{44}}}=  2.431

And if we use the z score we got:

P(z>2.431) =1-P(z

6 0
2 years ago
What percent of 75.5 is 81.54
Lady bird [3.3K]
I got the answer of 6127.731 hope this works out for you.
4 0
2 years ago
Use parentheses to make 5+4×3×3
kherson [118]
The aNSWER IS 41..AM I RIGHT?
3 0
2 years ago
Read 2 more answers
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