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Scorpion4ik [409]
2 years ago
8

From the above histogram find out which age group teachers are most in the school​

Mathematics
1 answer:
Anna35 [415]2 years ago
6 0
You need to provide the above histogram.
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I will mark as the brainliest answer
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The scale factor from the small one to the big one is 3
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3 years ago
What are the similarities and differences between the standard form and vertex form of a quadratic equation?
guajiro [1.7K]

Answer and Step-by-step explanation: <u>Standard</u> <u>form</u> of a quadratic equation is expressed as: y=ax²+bx+c, while <u>vertex</u> <u>form</u> is written as:

y=a(x-h)²+k.

The similarities between standard and vertex forms is that they show if the graph of the equation has a <u>minimum</u> (when a>0) or <u>maximum</u> (a<0) and it's easier to determine the y-intercept: for standard, the value of c is the intercept; for vertex, the value k is the intercept.

The advantage of standard form is that you can determine the product and sum of the equation's roots, which is a method to determine them.

The advantages of vertex form are: easier to find the vertex of the graph, which is the pair (h,k) and the axis of symmetry, which is the value of h.

8 0
3 years ago
Zzyzx Road is in California near Nevada. How many five-letter arrangements of the letters in the English alphabet follow Zzyzx a
Nutka1998 [239]
XyzzZ That's It I think.
7 0
3 years ago
A company introduces a new product for which the number of units sold S is
KonstantinChe [14]
(a) The "average value" of a function over an interval [a,b] is defined to be 

(1/(b-a)) times the integral of f from the limits x= a to x = b. 

Now S = 200(5 - 9/(2+t)) 

The average value of S during the first year (from t = 0 months to t = 12 months) is then: 

(1/12) times the integral of 200(5 - 9/(2+t)) from t = 0 to t = 12 

or 200/12 times the integral of (5 - 9/(2+t)) from t= 0 to t = 12 

This equals 200/12 * (5t -9ln(2+t)) 

Evaluating this with the limits t= 0 to t = 12 gives: 

708.113 units., which is the average value of S(t) during the first year. 


(b). We need to find S'(t), and then equate this with the average value. 

Now S'(t) = 1800/(t+2)^2 

So you're left with solving 1800/(t+2)^2 = 708.113 

<span>I'll leave that to you</span>
6 0
2 years ago
Prove Euler's identity using Euler's formula.<br> e^ix = cos x + i sin x
Korolek [52]

First list all the terms out.

e^ix = 1 + ix/1! + (ix)^2/2! + (ix)^3/3! ...

Then, we can expand them.

e^ix = 1 + ix/1! + i^2x^2/2! + i^3x^3/3!...

Then, we can use the rules of raising i to a power.

e^ix = 1 + ix - x^2/2! - ix^3/3!...

Then, we can sort all the real and imaginary terms.

e^ix = (1 - x^2/2!...) + i(x - x^3/3!...)

We can simplify this.

e^ix = cos x + i sin x

This is Euler's Formula.

What happens if we put in pi?

x = pi

e^i*pi = cos(pi) + i sin(pi)

cos(pi) = -1

i sin(pi) = 0

e^i*pi = -1 OR e^i*pi + 1 = 0

That is Euler's identity.

3 0
3 years ago
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