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Vedmedyk [2.9K]
2 years ago
9

Please answer I’ll give brainly please help I’m begging you

Mathematics
1 answer:
andrew11 [14]2 years ago
7 0

Answer:

option A. y = 1/2 x

Step-by-step explanation:

given the equation:

y - 9 = 1/2 ( x - 3 )

here the gradient is 1/2

if passes parallel the gradient is same.

the line pass through ( -2 , -1 )

so,

y - y1 = m( x -  x1 )

y - - 1 = 1/2 ( x - -2 )

y + 1 = x/2 + 1

y = 1/2 x

Therefore option A is correct.

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Can you please help me?!
Fudgin [204]

Answer:

A and B are correct

Step-by-step explanation:

4 0
2 years ago
(X-3)(x+2)=0 find the zeros
Ivanshal [37]

Answer: Min = (0.5, −6.25)

Step-by-step explanation: Standard form:

x2 − x − 6 = 0

Factorization:

(x + 2)(x − 3) = 0

Solutions based on factorization:

x + 2 = 0   ⇒   x1 = −2

x − 3 = 0   ⇒   x2 = 3

6 0
3 years ago
1+2g=-7 how do you do this?
blsea [12.9K]

Answer:

you would - 1 to -7 and get -8 then divide -8 by -2 than it would be 4


Step-by-step explanation:


8 0
3 years ago
Read 2 more answers
A bill for Rs 3235 was drawn on Feb. 3, 1998 at 6 months and discounted on March 3, 1998 at 8 % p.a. Find the value of the bill
Fantom [35]

Answer:

RS 3127.166

RS 107.834

Step-by-step explanation:

6 month bill :

Drawn date = Feb, 3

Discounted date = March 3,

Difference = 1 month

6 month - 1 month = 5 months = 5 * 30 = 150 days

Value of the bill :

P(1 - rate * time)

3235(1 - 0.08 * 150/360)

3235(1 - 0.08 * 0.4166666)

3235(1 - 0.0333333)

3235(0.9666666)

= Rs3127.1666

Value of bill = 3127.166

Bankers gain = 3235 - 3127.166 = 107.834

6 0
3 years ago
Researchers have found that after 25 years of age the average size of the pupil in a
laila [671]

Answer:

At 25 = 6.8612mm

At 50 years = 5.422mm

Step-by-step explanation:

Equation,

d = 2.115Logₑa + 13.669

d = diameter of the pupil

a = number of years

Note : Logₑa = In a (check logarithmic rule)

d = 2.115Ina + 13.669

1. At 25 years,

d = -2.115In25 + 13.669

d = -2.115 × 3.2188 + 13.669

d = -6.807762 + 13.669

d = 6.8612mm

At 25 years, the pupil shrinks by 6.86mm

2. At 50 years,

d = -2.1158In50 + 13.669

d = -2.1158 * 3.912 + 13.669

d = -8.2770 + 13.699

d = 5.422mm

At 50 years, the pupil shirks by 5.422mm

To save this question, I had to plug in the values into the equation.

Solving for Logₑa might be difficult, so instead I used Inx which is the same thing. Afterwards, i substituted in the values and solve the equation for each years.

8 0
3 years ago
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