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2 years ago

The original price is $60.The sales price is $45. What is the percent of discount?

1 answer:

5 0

Hey there!

To start, first subtract 45 from 60 to find the amount of money taken off from the discount:
60-45
=15

Because 15 dollars have been taken off the original price, you can find the percent of discount by setting up this proportion where x represents the percent of discount:
15/60=x/100

Now, cross multiply and solve for x:
1500=60x
x=25

Therefore, your discount would be 25%.

Hope this helps and have a marvelous day! :)

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2 years ago

The equation y=0.002x-0.20 can be used to determine the approximate profit,y in dollars,of producing x items.solve for x. How ma

lakkis [162]

Answer:

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Step-by-step explanation:

from the equation y = 0.002x -0.20

where y is the profit in dollars

and x is the number of items

then to get the number of item to be produced in other to profit $3933 ?

will be by substituting $3933 for y in the equation and solving for x,

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Firstly you will add 0.20 to both sides, which will be

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3 years ago

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sertanlavr [38]

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2 years ago

Joey and Armando live on the same st as the park. The park is 9/10 mile from Joey's home. Joey leaves home and walks to Armando'

AleksandrR [38]

Let's start by assuming Armando's house is between Joey's and the park.

Let $x$ be the distance Joey walked to Armando's house.

<span>The park is 9/10 mile from Joey's home. Joey leaves home and walks to Armando's home. Then Joey and Armando walk 3/5 mile to the park.

</span> $\dfrac{9}{10} = x + \dfrac{3}{5}$

$x = \dfrac{9}{10} - \dfrac{3}{5} = \dfrac{9}{10} -\dfrac{6}{10} = \dfrac{3}{10}$

That's probably the answer they're looking for. But what if the park is between Joey and Armando's houses or Joey is between the park and Armando? (The latter isn't really possible with the given distances.)

Let $a, b, c$ be the distances between three collinear points like we have here. Our equation is really a few equations in one, something like

$\pm a \pm b = \pm c$

Let's get rid of the plus/minuses. Squaring,

$a^2 + b^2\pm 2ab = c^2$

$\pm 2ab = c^2-a^2-b^2$

$4a^2b^2 = (c^2-a^2-b^2)^2$

For us, that's a quadratic equation for $c^2$

$4(9/10)^2(3/5)^2= (c^2-(9/10)^2 - (3/5)^2)^2$

I'll skip right to the solutions,

$c^2=\dfrac{9}{100} \textrm{ or } c^2=\dfrac{9}{4}$

$c=\dfrac{3}{10} \textrm{ or } c=\dfrac{3}{2}$

We could have gotten the 3/2 just by adding 9/10+3/5 but this was more fun.

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3 years ago