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3 years ago

Which algebraic expression is equivalent to the expression below? (6x + 13) + 6

Mathematics

1 answer:

finlep [7]3 years ago

8 0

Answer:

6x+19

Step-by-step explanation:

The parentheses do nothing here to stop you from adding - since every term in here is only being added, there is no reason to worry about the parentheses. Simply combine like terms (13 + 6) to achieve 6x + 19.

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Find the missing value so that the two points have a slope of -3/10 (x,-8) and (-5,-5)

rosijanka [135]

Answer:

Step-by-step explanation:

The slope is given by

m = (y2-y1)/(x2-x1)

-3/10 = (-5--8)/(-5-x)

-3/10 = (-5+8)/(-5-x)

Using cross multiplication

-3 (-5-x) = 10*(-5+8)

Simplify

-3(-5-x) =10(3)

Divide by -3

-3/-3(-5-x) =10(3)/-3

-5-x = -10

Add 5 to each side

-5-x+5 = -10+5

-x=-5

Divide by -1

x=5

4 0

3 years ago

2. Find the 20th term of an arithmetic sequence if its 6th term is 14 and 14th term is 6.

Fudgin [204]

Answer:

$\sf t_{20}= 0$

Step-by-step explanation:

<h3>Arithmetic sequence:</h3>

$\sf \boxed{\bf n^{th} \ term = a + (n-1)d}\\\\\text{Here, a is the first term ; d is the common difference }$

6th term is 14 ⇒ $\sf t_6 = 14$

a + (6 - 1)d = 14

a + 5d = 14 --------------(I)

14th term is 6 ⇒ $\sf t_{14} = 6$

a + (14-1)d = 6

a + 13d = 6 ----------------(II)

Subtract equation (II) from equation(I)

(I) a + 5d = 14

(II) a + 13d = 6

-8d = 8

d = 8 ÷(-8)

$\sf \boxed{\bf d= (-1)}$

Plugin d = -1 in equation (I)

a + 5(-1) = 14

a -5 = 14

a = 14 + 5

$\sf \boxed{\bf a = 19}$

20th term:

$\sf t_{20}= 19 + 19*(-1)$

= 19 - 19

$\sf \boxed{\bf t_{20} = 0}$

8 0

2 years ago

Read 2 more answers

Evaluate 9!/6!3! <br><br><br> plz helppp:)))

Helga [31]

Answer:

84 :-)

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

.....................

Ivahew [28]

1.) Parallelogram

2.) Quadrilateral

3.) Complimentary

4.) bisect

5.) Supplementary

6.) GH = 14 units

7.) 80°

8.) KF = 10

7 0

2 years ago

Is 3^100/3^99 greater than,less than, or equal to 3??

oksian1 [2.3K]

Answer:

$\frac{3^{100}}{3^{99}} = 3$

Step-by-step explanation:

$\frac{a^{m}}{a^{n}}=a^{m-n}, m>n\\\\$

Therefore,

$\frac{3^{100}}{3^{99}}=3^{100-99}=3^{1}=3\\\\\frac{3^{100}}{3^{99}} = 3$

6 0

3 years ago