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3 years ago

Consider the exponential function f(x) = 2(3x) and its graph.

Mathematics

2 answers:

AveGali [126]3 years ago

6 0

Answer:

The initial value of the function is 2

The base of the function is 3

The function shows exponential growth

Step-by-step explanation:

f(x) = 2(3^x)

Exponential functions are those with the following equation:

y = a*b^x

where a ≠ 0, b > 0 and b ≠ 1 and x is a real number.

a is the y-intercept and b is the base.

The initial value of the function is the same as the y-intercept

If a is positive, the function growth. If a is negative, the function decay

geniusboy [140]3 years ago

6 0

Answer:

The initial value of the function is 2

The base of the function is 3

The function shows exponential growth

Step-by-step explanation:

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A silo is a composite of a cylindrical tower with a cone for a roof. What is the volume of the silo if the radius of the base is

kirza4 [7]

Answer:

The answer is b. 343,480.8ft

Step-by-step explanation:

I thought it was c at first because I forgot to add the volume of the cone.

The equation for the volume of a cylinder is V=π×r²×h

The solution would look like V=π40²×65=326725.8

The equation for the volume of a cone is V=1/3πr²×h

The solution would look like V=1/3π×40²×10=16755

Adding the two volumes would equal 326725.8±16755= 343480.8

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2 years ago

Compare your estimate to the exact quotient. Does your quotient seem reasonable? Explain your answer. 9 1/3 ÷ 2 3/4

dezoksy [38]

Answer:

(9(3)+1)/3÷(2(4)+3)/4

28/3÷11/4

28/3×4/11

112/33

3.393

3 0

2 years ago

Date : n _ 5+ [ 4 +(-7) -{ 6 ×(5+ 1x4)}]

s2008m [1.1K]

Answer:

−28−6^2x4

Step-by-step explanation:

6 0

2 years ago

D^2(y)/(dx^2)-16*k*y=9.6e^(4x) + 30e^x

MA_775_DIABLO [31]

The solution depends on the value of $k$ . To make things simple, assume $k>0$ . The homogeneous part of the equation is

$\dfrac{\mathrm d^2y}{\mathrm dx^2}-16ky=0$

and has characteristic equation

$r^2-16k=0\implies r=\pm4\sqrt k$

which admits the characteristic solution $y_c=C_1e^{-4\sqrt kx}+C_2e^{4\sqrt kx}$ .

For the solution to the nonhomogeneous equation, a reasonable guess for the particular solution might be $y_p=ae^{4x}+be^x$ . Then

$\dfrac{\mathrm d^2y_p}{\mathrm dx^2}=16ae^{4x}+be^x$

So you have

$16ae^{4x}+be^x-16k(ae^{4x}+be^x)=9.6e^{4x}+30e^x$
$(16a-16ka)e^{4x}+(b-16kb)e^x=9.6e^{4x}+30e^x$

This means

$16a(1-k)=9.6\implies a=\dfrac3{5(1-k)}$
$b(1-16k)=30\implies b=\dfrac{30}{1-16k}$

and so the general solution would be

$y=C_1e^{-4\sqrt kx}+C_2e^{4\sqrt kx}+\dfrac3{5(1-k)}e^{4x}+\dfrac{30}{1-16k}e^x$

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2 years ago

12 divided into a number is wat

Irina-Kira [14]

Answer:

Step-by-step explanation:

3 0

2 years ago

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