Answer:
m=2 and n=3
Step-by-step explanation:
<u>Step</u> :-
Given ![[ 2 x^{n}y^{2} ]^m = 4 x^6 y^4](https://tex.z-dn.net/?f=%5B%202%20x%5E%7Bn%7Dy%5E%7B2%7D%20%5D%5Em%20%3D%204%20x%5E6%20y%5E4)
using algebraic formula 
now
now equating 'x' powers, we get
....(1)
now
Equating 'y' powers ,we get
2 m=4
m=2
substitute m= 2 in equation (1)
we get
2 n=6
n=3
verification:-
substitute m=2 and n=3 , we get
both are equating so m= 2 and n=3
Answer:
1 +√21 + 1 - √21
2 2
Step-by-step explanation:
Answer:
Patricia spent $24 on presents, while Donald spent $12 and Carl spent $36.
Step-by-step explanation:
The problem is to solve how much money each person spent on presents in the year, through a series of equivalences. In order to determine how much money each one spent, the following equation must be proposed:
Patricia = X
Donald = 1 / 2X
Carl = 3/2 X
X + 1 / 2X + 3 / 2X = 72
1X + 0.5 X + 1.5 X = 72
3X = 72
X = 72/3
X = 24
Thus, Patricia spent $ 24 on presents, while Donald spent $ 12 (2/24) and Carl spent $ 36 (1.5 x 24).
Answer:
i believe it is B.
I could be wrong, D is my second choice. but since (left to right) its decreasing, im 89% sure it is B 1/9.
Answer:
3 and -5
Step-by-step explanation:
