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3 years ago

-2•f(-6) - 7•g(-7) Can someone please help me

Mathematics

1 answer:

pantera1 [17]3 years ago

5 0

Answer:

Your answer is: 12f + 49g

Simplify each term.

Step-by-step explanation:

Hope this helped : )

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Possible values for the area A of the rectangle shown are 12

KatRina [158]

Answer:

idc its 12

Step-by-step explanation:

5 0

3 years ago

Find the compound interest compounded annually on rupees 2700 rate 6 ⅔% per annum and time is 2 years

dalvyx [7]

<u>Answer:</u>

plz mark me as brainliest ...TOOK ME LONG TIME TO TYPE

answer = CI = 3108 RUPEES

<u>Step-by-step explanation:</u>

i am doing the method in which u find the simple interest of first year then second year.

SI FOR 1ST YEAR= P X R X T / 100

SI = 2700 X 20 X 2 / 3 X 100 ( RATE OF INTEREST IS 20 / 3)

SI = 108000/300

SI = 360

SI FOR SECOND YEAR =

P = 2700 + 360= 3060

SI = 3060 X 20 X 2 / 300

SI= 122400 / 300

SI = 408

COMPOUND INTEREST (CI) = PRINCIPLE + SI OF 2ND YEAR

CI = 2700 + 408

CI = 3108 RUPEES

or u can solve be the method

CI = amount - principle

Amount= principle x (change in ratio) raised to time

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6 0

3 years ago

Read the following bar graph and answer the following related questions :

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3 years ago

Read 2 more answers

The length of a 200 square foot rectangular vegetable garden is 4feet less than twice the width. Find the length and width of th

inna [77]

Answer:

Length = 18.099 ft

Width = 11.049 ft

Step-by-step explanation:

let the length of the field be x ft

and the width be y ft

as per the condition given in problem

x=2y-4 -----------(A)

Also the area is given as 200 sqft

Hence

xy=200

Hence from A we get

y(2y-4)=200

taking 2 as GCF out

2y(y-2)=200

Dividing both sides by 2 we get

$y(y-2)=100$

$y^2-2y=100$

subtracting 100 from both sides

$y^2-2y-100=0$

Now we solve the above equation with the help of Quadratic formula which is given in the image attached with this for any equation in form

$ax^2+bx+c=0$

Here in our case

a=1

b=-1

c=-100

Putting those values in the formula and solving them for y

$y=\frac{-(-2)+\sqrt{(-2)^2-4 \times (-1) \times 100}}{2 \time 1}$

$y=\frac{-(-2)-\sqrt{(-2)^2-4 \times (-1) \times 100}}{2 \time 1}$

Solving first

$y=\frac{2+\sqrt{4+400}{2}$

$y=\frac{2+\sqrt{404}{2}$

$y=\frac{2+20.099}{2}$

$y=\frac{22.099}{2}$

$y=11.049$

Solving second one

$y=\frac{-(-2)-\sqrt{(-2)^2-4 \times (-1) \times 100}}{2 \time 1}$

$y=\frac{2-\sqrt{4+400}{2}$

$y=\frac{2-\sqrt{404}{2}$

$y=\frac{2-20.099}{2}$

$y=\frac{-18.99}{2}$

$y=-9.045$

Which is wrong as the width can not be in negative

Our width of the field is

y=11.099

Hence the length will be

x=2y-4

x=2(11.049)-4

x=22.099-4

x=18.099

Hence our length x and width y :

Length = 18.099 ft

Width = 11.049 ft

4 0

3 years ago

Find the slope of the line on the graph.

mars1129 [50]

Answer:

M= -3

Step-by-step explanation:

The two points on the graph are (0,4) and(1,1), using the slope formula you get a slope of - 3

3 0

3 years ago