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Artemon [7]
4 years ago
9

What is the probability of getting a gray offspring

Biology
1 answer:
VladimirAG [237]4 years ago
4 0
I think it is like 50%
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The iris of the human eye can have many colors, including brown, blue, green, and hazel. How does polygenic inheritance explain
elena55 [62]

Answer: The color of the iris is the example of polygenic inheritance.

Explanation:

Polygenic inheritance can be defined as the inheritance in which one trait is controlled by the two or more than two genes. The color of the skin, color of iris, weight and height are polygenic traits. The color of the iris is the polygenic trait the number of genes responsible for this are unknown but these genes are responsible for the synthesis of melanin pigment imparting color to the iris. OCA2 and HERC2 are the chief genes present on chromosome 15 responsible for this trait. Dark brown and black eyes are expected to have more amount of melanin as compared to the green and hazel eyes.

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In sickle cell disease , variation in one gene causes red blood cells to bend , or sickle this means the sickled cells
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Which carbohydrate can be used by the body as an immediate source of protein?
snow_lady [41]

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Glucose is the bodies primary form of fuel

Explanation:

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3 years ago
Which of the following is a negative consequence of air pollution on people?
DIA [1.3K]
The answer would be more lung disease
3 0
3 years ago
Assume a population of purple and white flower pea plants (2000 total plants) is in Hardy-Weinberg equilibrium. The frequency of
lys-0071 [83]

Answer:

a) 0.48

b)

p= 0.4\\q=0.6

c) 720

Explanation:

Given ,

Frequency of white flower plant (p^2) is 0.16

Thus, frequency of dominant white allele (p) is equal to \sqrt{0.16} \\= 0.4

As we that, as per  Hardy-Weinberg equilibrium equation

p+q=1

Substituting the value of p in above equation, we get

0.4+q=1\\q=1-0.4\\q=0.6

a) As per Hardy-Weinberg equilibrium equation

p^2+q^2+2pq=1\\

Substituting the given and calculated values in above equation, we get -

0.4^2+0.6^2+2pq=1\\0.16+0.36+2pq=1\\2pq=1-0.16-0.36\\2pq=0.48

b) The frequency (decimal form) of the dominant allele

p= 0.4\\q=0.6

c) number of homozygous purple flower plants

= frequency of purple flower plants (q^2) * Number of flowers

= q^2 * 2000\\= (0.6^2)*2000\\= 0.36 * 2000\\= 720

8 0
3 years ago
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