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3 years ago

8

Can someone please help me out on this? :P

2 answers:

kiruha [24]3 years ago

7 0

The first one: They are telling you that 1 inch = 1 foot, and the window width is already 4 inches so since your going to convert into feet then look at the “key” and think okay if 1 inch = 1 foot then how many feet does 4 inches equal it would be 4ft
The second question: It’s saying two cities are 5 3/4 inches apart and for every 1/2 inch = 3 miles so first you would take 5 3/4 and divide 1/2 you would get 11 1/2 but that’s not the answer that’s how many inches in all so you would take 11 1/2 and multiply 3 to get how many miles so the answer is 34 1/2 miles
I hope this helps I tried to explain as much as I can so you won’t have trouble on this kinda stuff again:))

zvonat [6]3 years ago

7 0

The first one would be four feet and the second would be 34 and 1/2 miles

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padilas [110]

Answer:

$Area = x^2- 25$

$Area =9x^2 +24x + 16$

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Step-by-step explanation:

Solving (1):

$Length = (x + 5)$

$Width = (x - 5)$

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$Area = Length * Width$

$Area = (x + 5) * (x - 5)$

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Given

$Length = (3x + 4)$

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$Area =Length * Length$

$Area =(3x + 4) * (3x + 4)$

$Area =9x^2 + 12x + 12x + 16$

$Area =9x^2 +24x + 16$

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$Area = 3x^2 + 7x - 6$

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Required: Calculate Length

$Area = Length * Width$

$Length = \frac{Area}{Width}$

$Length = \frac{3x^2 + 7x - 6}{x + 3}$

Factorize the numerator

$Length = \frac{3x^2 + 9x -2x - 6}{x + 3}$

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Divide by x + 3

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$Distance = (2y^3 - 7y^2 + 5y -1)$

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$Speed = \frac{Distance}{Time}$

$Speed = \frac{2y^3 - 7y^2 + 5y -1}{2y - 1}$

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$Speed = \frac{\left(2y-1\right)\left(y^2-3y+1\right)}{2y - 1}$

$Speed = \left(y^2-3y+1\right)$

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First, calculate the sum:

$Sum = m + 3 + 2m - 3$

$Sum = m + 2m+3 - 3$

$Sum = 3m$

Then, the product

$Product = (m^2 + 2m - 2)(3m)$

$Product = 3m^3 + 6m^2 - 6m$

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