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Nikolay [14]
3 years ago
8

21 is 75% of what number? I don't get it.

Mathematics
2 answers:
Artist 52 [7]3 years ago
8 0
21=75/100x
2100=75x
X=2100/75=28
Rina8888 [55]3 years ago
7 0
21 is 75% of 28. If you use a calculator, you can just put 21×100÷75. Or if you need to do it on paper, you could do...

1. do 75/100×21

2.multiply both sides by 100 and the divide by 75
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On a citrus farm, the average annual yield of oranges is 124 pounds per tree when the number of trees is 22 per acre. For each a
ELEN [110]

Answer:

Number of orange trees = 3528

Step-by-step explanation:

Given: Average annual orange yield = 124 pounds (lbs) per tree

Number of trees = 22 per acre

Each tree produces 124 pounds, so 22 trees will produce

124*22 = 2728 lbs per acre

For every additional tree over 22, 2 pounds per tree is lost.

So, if you add x trees, you lose 2x pounds.

Thus, we have the function:

f(x) = (124 - 2x)*(22 + x) for the added tree(s)

f(x) = 2728 + 80x - 2x^{2}

For quadratic equations like this, the maximum(or minimum) is obtained by substituting x= -b/2a into the given equation. a and b are obtained from the general form of a quadratic equation:

y =ax^{2} + bx + c

Comparing this with f(x), we have that

a = -2 (coefficient of x2)

b = 80 (coefficient of x)

Using these values in x = -b/2a, we get

x = -\frac{80}{2*(-2)} = 20

So, use x = 20 in the maximum function we got earlier

f(x) = 2728 + 80(20) -2(20^{2}) = 2728 + 1600 - 800\\ \\f(x) = 3528

Therefore, the number of oranges that should be planted in order to maximize the number of pounds of oranges per acre = 3528

3 0
3 years ago
If c=5 and d=4<br> what is 6c squared minus 5d plus 8?
Ymorist [56]
6c^2-5d+8
6 (5)^2-5(4)+8
30^2-20+8
900-20=8
880-8=872
ANSWER:872

5 0
3 years ago
Can someone solve this for me
Licemer1 [7]

Answer:

slope is 2 and y-intercept is 5

Step-by-step explanation:

3 0
4 years ago
What number makes the equation true?<br> 4= 36 :<br> PLZZZZZ HELP
babymother [125]

Answer:

9x4=36

Step-by-step explanation:

8 0
4 years ago
Oleg, Sasha, and Dima share 600 toys. Sasha has twice as many toys as Oleg. Dima has 40 more toys than Oleg. How many toys does
Anika [276]

Answer: 140

Oleg, Sasha, and Dima shared 600 toys. Sasha had twice as many toys as Oleg. Dima had 40 more toys than Oleg.

Let the number of toys Oleg has = x

Let the number of toys Sasha has = y

Let the number of toys Dima has = z

Sasha had twice as many toys as Oleg

So y = 2*x= 2x

Dima had 40 more toys than Oleg.

z = x + 40

Oleg, Sasha, and Dima shared 600 toys

x + y + z= 600

We know y=2x and z=x+40

Replace it for y and z

Subtract 40 on both sides

Divide by 4 on both sides

Oleg had 140 toys

Step-by-step explanation:

6 0
4 years ago
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