Well i can't really help you in this since i do not know the cost of each calendar, but if you need the formula.
the cost of one calendar = x
so the total cost would be 200 times x (200x)
From the diagram above,
XZ = 10 in and OX = 10 in
we are to find length of OY
XZ is a chord and line OY divides the chord into equal length
Hence, ZY=YX= 5 in
Now we solve the traingle OXY
To find OY we solve using pythagoras theorem

applying values from the triangle above
![\begin{gathered} OX^2=XY^2+OY^2 \\ 10^2=5^2+OY^2 \\ 100=25+OY^2 \\ OY^2\text{ = 100 -25} \\ OY^2\text{ = 75} \\ OY\text{ = }\sqrt[]{75} \\ OY\text{ = }\sqrt[]{25\text{ }\times\text{ 3}} \\ OY\text{ = 5}\sqrt[]{3\text{ }}in \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20OX%5E2%3DXY%5E2%2BOY%5E2%20%5C%5C%2010%5E2%3D5%5E2%2BOY%5E2%20%5C%5C%20100%3D25%2BOY%5E2%20%5C%5C%20OY%5E2%5Ctext%7B%20%3D%20100%20-25%7D%20%5C%5C%20OY%5E2%5Ctext%7B%20%3D%2075%7D%20%5C%5C%20OY%5Ctext%7B%20%3D%20%7D%5Csqrt%5B%5D%7B75%7D%20%5C%5C%20OY%5Ctext%7B%20%3D%20%7D%5Csqrt%5B%5D%7B25%5Ctext%7B%20%7D%5Ctimes%5Ctext%7B%203%7D%7D%20%5C%5C%20OY%5Ctext%7B%20%3D%205%7D%5Csqrt%5B%5D%7B3%5Ctext%7B%20%7D%7Din%20%5Cend%7Bgathered%7D)
Therefore,
Length of OY =
So, we already know that one hive has a weight of 11.607kg and .204kg is add each week, so we add on .204kg times, w, representing weeks onto 11.607kg and our t is our total of weight of a hive with respect to weeks

So in this case our w is 7.5 weeks and now we evaluate t

Solve

Answer:
Hive's weight will increase by 1.53kg in 7.5 weeks to 13.137kg
Answer:
45595
Step-by-step explanation:
plug in 7 for n and solve
This is the population 7 years after 2002(2009)
Answer:
V = 396 cm³
Step-by-step explanation:
the volume (V) of the prism is calculated as
V = Ah ( A is the area of the triangular face and h the height of prism )
A =
bh ( b is base and h perpendicular height )
here b = 9, h = 8 , then
A =
× 9 × 8 = 4.5 × 8 = 36 cm² , so
V = 36 × 11 = 396 cm³