178.
If number CLXXVIII is within to text or sentence it should be read in its equivalent in arabic numbers, in this case 178.
:)
Step-by-step explanation:
A supplementary angle is an angle that is 180 degrees. We are given two angles that add up to 180, but we need to solve for x first.
The first step is to solve both angles. We know that both angles added together are supplementary, so they are equal to 180.
4x + 8 = unknown angle
6x + 3 = unknown angle
(4x + 8) + (6x + 3) = 180
Because we know a supplementary angle is 180 degrees, we can solve for x to find both angles.
Solve for x.
(4x + 8) + (6x + 3) = 180
10x + 11 = 180
10x = 169
x = 16.9
Now, we know the value of x, so we plug in x for both angles to determine which angle is smaller.
4x + 8
4(16.9) + 8
67.6 + 8 = 75.6 degrees
and the other angle
6x + 3
6(16.9) + 3
101.4 + 3 = 104.4 degrees
Now we know that the smaller angle is 75.6 degrees.
Also, to make sure the math is correct, when plugging in both numbers after finding x, they should add to 180.
75.6 + 104.4 = 180 so we know they are supplementary for sure.
Good luck!
Answer: D
Step-by-step explanation: I think
A triangle is a three-edged polygon with three vertices. ΔAKE and ΔCKP are congruent.
<h3>What is a triangle?</h3>
A triangle is a three-edged polygon with three vertices. It is a fundamental form in geometry. The sum of all the angle of a triangle is always equal to 180°.
In ΔABC, since AB≅BC, therefore, the triangle will be an isosceles triangle, and the measure of ∠A ≅ ∠C, using the base angle theorem.
Now In ΔAKE and ΔCKP,
∠A ≅ ∠C {Proved above}
∠AKE ≅ ∠CKP {Given}
AK ≅ KC {Given }
Since two angles and a side of the triangle are equal, therefore, we can write the two triangle are congruent using the Side-angle-side or Angle-Side-Angle congruence.
Hence, ΔAKE and ΔCKP are congruent.
Learn more about Triangle:
brainly.com/question/2773823
#SPJ1
Answer:
a) P(Y > 76) = 0.0122
b) i) P(both of them will be more than 76 inches tall) = 0.00015
ii) P(Y > 76) = 0.0007
Step-by-step explanation:
Given - The heights of men in a certain population follow a normal distribution with mean 69.7 inches and standard deviation 2.8 inches.
To find - (a) If a man is chosen at random from the population, find
the probability that he will be more than 76 inches tall.
(b) If two men are chosen at random from the population, find
the probability that
(i) both of them will be more than 76 inches tall;
(ii) their mean height will be more than 76 inches.
Proof -
a)
P(Y > 76) = P(Y - mean > 76 - mean)
= P( 
) > 
)
= P(Z > )
= P(Z > 
)
= P(Z > 2.25)
= 1 - P(Z ≤ 2.25)
= 0.0122
⇒P(Y > 76) = 0.0122
b)
(i)
P(both of them will be more than 76 inches tall) = (0.0122)²
= 0.00015
⇒P(both of them will be more than 76 inches tall) = 0.00015
(ii)
Given that,
Mean = 69.7,
= 1.979899,
Now,
P(Y > 76) = P(Y - mean > 76 - mean)
= P( 
)) > 
)
= P(Z > )
= P(Z > 
))
= P(Z > 3.182)
= 1 - P(Z ≤ 3.182)
= 0.0007
⇒P(Y > 76) = 0.0007
