Answer:
D. all of these are correct
Explanation:
option d is correct answer
Outlook is a software program that provides for e-mail communication
Answer:
35
Explanation:
List E is a 2 dimensional array. We want index 1 of E, which is B. Now we have an index of that list B, it is index 0 so 35.
In c# and java it's indexOf
To accomplish this without using a loop,
we can use math on a string.
Example:
print("apple" * 8)
Output:
appleappleappleappleappleappleappleapple
In this example,
the multiplication by 8 actually creates 8 copies of the string.
So that's the type of logic we want to apply to our problem.
<span>def powersOfTwo(number):
if number >= 0:
return print("*" * 2**number)
else:
<span>return
Hmm I can't make indentations in this box,
so it's doesn't format correctly.
Hopefully you get the idea though.
We're taking the string containing an asterisk and copying it 2^(number) times.
Beyond that you will need to call the function below.
Test it with some different values.
powersOfTwo(4) should print 2^4 asterisks: ****************</span></span>