F(-1)....this is basically saying that x = -1...and when x = -1 (according to ur chart), then f(-1) = 0 <==
2 feet in a second 12 inches in a foot
Answer:
y = 4/3x +8/3
Step-by-step explanation:
The point-slope form is ...
y -k = m(x -h) . . . . . . . line with slope m through point (h, k)
For the given point and slope, this is ...
y -4 = 4/3(x -1)
Adding 4 and eliminating parentheses, you have ...
y = 4/3x -4/3 +4
y = 4/3x +8/3
Answer:
11x + 10y - 2w
Step-by-step explanation:
Hello!
To solve for the perimeter, we add up the like terms.
What are like terms?
Like terms are terms with the same variable and degree. 4x and 5y are NOT like terms because the variable is not the same. However, 4x and 3x are like terms, as adding them gives us 7x.
4x and 4x² are not like terms, because the degree of 4x is 1 (degree means the largest exponent), but the degree of 4x² is 2.
Solve for Perimeter:
Combine the like terms by adding them up.
- Perimeter = (8x - 4w) + (3y + 2w) + (3x + 7y)
- P = 8x - 4w + 3y + 2w + 3x + 7y
- P = 8x + 3x + 3y + 7y - 4w + 2w
- P = 11x + 10y - 2w
The perimeter is 11x + 10y - 2w
Answer:
Matrix transformation = ![\left[\begin{array}{ccc}-1&0\\0&1\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-1%260%5C%5C0%261%5Cend%7Barray%7D%5Cright%5D)
Vertices of the new image: P'= (5,-2), Q'= (6,-3), R'= (2,-3)
Step-by-step explanation:
Transformation by reflection will produce a new congruent object in different coordinate. Reflection to y-axis made by multiplying the x coordinate with -1 and keep the y coordinate unchanged. The matrix transformation for reflection across y-axis should be: .
To find the coordinate of the vertices after transformation, you have to multiply the vertices with the matrix. The calculation of the each vertice will be:
P'= ![\left[\begin{array}{ccc}-5\\-2\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-5%5C%5C-2%5Cend%7Barray%7D%5Cright%5D)
= (5,-2)
Q'= ![\left[\begin{array}{ccc}-6\\-3\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-6%5C%5C-3%5Cend%7Barray%7D%5Cright%5D)
= (6,-3)
R'= ![\left[\begin{array}{ccc}-2\\-3\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-2%5C%5C-3%5Cend%7Barray%7D%5Cright%5D)
= (2,-3)
