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saw5 [17]
3 years ago
13

What value of y makes the 2 triangles congruent by SSS?

Mathematics
1 answer:
aleksandrvk [35]3 years ago
8 0
The triangle was just flipped so the missing side is going to equal 36, so...
2y+20= 36
(Subtract 20 from each side to isolate the 2y)
2y= 16
(Divide each side by 2 to isolate the variable)

ANSWER:
y= 8
You might be interested in
The length of the longer leg of a right triangle is
Harman [31]
A and b are legs
a^2+b^2=c^2
lets say
a>b

so
a=13+3b
c=14+3b

a^2+b^2=c^2
(13+3b)^2+b^2=(14+3b)^2
9b^2+78b+169+b^2=9b^2+84b+196
10b^2+78b+169=9b^2+84b+196
minus 9b^2 both sides
b^2+78b+169=84b+196
minus 84b both sides
b^2-6b+169=196
minus 196 both sides
b^2-6b-27=0
factor
(b+3)(b-9)=0
set to zero
b+3=0
b=-3, false, dimentions cannot be negative

b-9=0
b=9

shorter leg is 9

a=13+3b
a=13+3(9)
a=13+27
a=40

c=14+3b
c=14+27
c=41

side legnths are
9in, 40in, 41in
3 0
3 years ago
The kings ship sank with 8 gold bars aboard. The king paid Captain Nemo 4/5 of one bar for finding the gold. The Captain gave 1/
Karo-lina-s [1.5K]
4/5×1/2= 2/5. If you want your answer in decimal form than it would be 0.4.
4 0
3 years ago
Whats her errors and whats the soulution​
kondor19780726 [428]

Answer:

she messed up at -17=34x

Step-by-step explanation:

she added 8x to each side but she was actually supposed to subtract

6 0
3 years ago
Read 2 more answers
Bob has a standard deck of playing cards. If he randomly draws a J, K, 2, and 2, what is the probability that the next card he d
nlexa [21]

Answer:

The correct answer has already been given (twice). I'd like to present two solutions that expand on (and explain more completely) the reasoning of the ones already given.


One is using the hypergeometric distribution, which is meant exactly for the type of problem you describe (sampling without replacement):


P(X=k)=(Kk)(N−Kn−k)(Nn)


where N is the total number of cards in the deck, K is the total number of ace cards in the deck, k is the number of ace cards you intend to select, and n is the number of cards overall that you intend to select.


P(X=2)=(42)(480)(522)


P(X=2)=61326=1221


In essence, this would give you the number of possible combinations of drawing two of the four ace cards in the deck (6, already enumerated by Ravish) over the number of possible combinations of drawing any two cards out of the 52 in the deck (1326). This is the way Ravish chose to solve the problem.


Another way is using simple probabilities and combinations:


P(X=2)=(4C1∗152)∗(3C1∗151)


P(X=2)=452∗351=1221


The chance of picking an ace for the first time (same as the chance of picking any card for the first time) is 1/52, multiplied by the number of ways you can pick one of the four aces in the deck, 4C1. This probability is multiplied by the probability of picking a card for the second time (1/51) times the number of ways to get one of the three remaining aces (3C1). This is the way Larry chose to solve the this.

Step-by-step explanation:


6 0
3 years ago
Read 2 more answers
PLEASE I NEED HELP I WILL MARK BRAINLYEST!!!!!!!!!!!!!!!!
koban [17]

Answer:

The amount is increasing and is increasing by 3.34% each year?

Step-by-step explanation:

Anything times a number higher than 1 will increase. 10125×1.83=18528.75.

6 0
3 years ago
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