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LuckyWell [14K]
3 years ago
8

The junior high band sold candy for a fundraiser the profit from the candy sale was 180.00 the girls sold 3 times as much as the

boys how much of the total profit did the girls provide
Mathematics
1 answer:
kaheart [24]3 years ago
3 0
Let the amount that the boys sold be x, the amount that girls sold will be 3x. The total will be given by:
x+3x=180
4x=180
solving for x we get:
x=180/4
x=45
Thus, boys sold $45, the girls provided 45*3=$135
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The low temperature on Monday was 16°F. On Tuesday, the low was 18°F cooler. On Wednesday, the low temperature was –4 times Tues
drek231 [11]

Answer:

-4(16-18), [16 + (-18)](-4)

Step-by-step explanation:

Given: The low temperature on Monday was 16°F. The low temperature on Tuesday was 18°F cooler. The low temperature on Wednesday was –4 times Tuesday’s temperature.

To find: expression that can be used to describe the low temperature on Wednesday

Solution:

Temperature on Monday = 16°F

So,

Temperature on Tuesday = (16-18)\°F

Temperature on Wednesday = -4(16-18)\°F

So, expression -4(16-18)=(16-18)(-4) can be used to describe the low temperature on Wednesday.

Also,

(16-18)(-4)=[16 + (-18)](-4)\,\,\left \{\because  (a-b)=\left [ a+(-b) \right ] \right \}

So, expression [16 + (-18)](-4) also represent temperature on Wednesday.

3 0
3 years ago
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For a continuous random variable X, P(20 ≤ X ≤ 40) = 0.15 and P(X > 40) = 0.16. Calculate the following probabilities. (Leave
yan [13]

Answer:

For a continuous random variable X, P(20 ≤ X ≤ 40) = 0.15 and P(X > 40) = 0.16.

Step-by-step explanation:

Here, P(x > 40) = 0.16

a). P(x < 40) = 1 - P(x > 40)

                   =  1 - 0.16

                    = 0.84

b). P(x < 20) = 1 - P(x\geq 20)

                    = 1 - {P(20 ≤ X ≤ 40) + P(X > 40)}

                    = 1 - (0.15 + 0.16 )  

                    = 1 - 0.31

                    = 0. 69

c). P(x = 40) = 0; The probability that a continuous variable assume a particular value is zero.

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3 years ago
Jimmy rolled a die 90 times and recorded the results. He got a one 15 times, a two 22 times, a three 18 times, a four 11 times,
vovikov84 [41]

Since in Jimmy's 90 times die roll six appeared 11 times, so the probability of face of sixes appearing is: \frac{11}{90}.

Thus , when the die is rolled 1500 times then it is obvious that the number of times the face of six will appear will also increase proportionately.

This proportionate increase in the number of times the face of six will appear will be given thus:

If six appears 11 times in 90 rolls then to find how many times it will appear in 1500 rolls is calculated as \frac{11}{90}=\frac{x}{1500} where x is the number of times the face of six will appear.

Thus, expression gives:

x=\frac{11}{90}\times 1500=\frac{11\times 50}{3}=\frac{550}{3}  \approx 183

Therefore, Jimmy can six's approximately 183 times if he rolled the die 1500 times.

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4 years ago
Literally answer any of the questions above and it’ll be the biggest help
Tcecarenko [31]

The cosine of an angle is the x-coordinate of the point where its terminal ray intersects the unit circle. So, we can draw a line at x=-1/2 and see where it intersects the unit circle. That will tell us possible values of θ/2.

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a) The cosine values repeat every 2π, so the general form of the smallest angle will be

... θ = 2(2π/3 + 2kπ) = 4π/3 + 4kπ

b) Similarly, the values repeat for the larger angle every 2π, so the general form of that is

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c) Using these expressions with k=0, 1, 2, we get

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Jennifer paid $3.75 for 3 doughnuts. What is the unit price for the doughnuts?​
Scrat [10]

Answer:

Cost of one doughnut = $1.25

Step-by-step explanation:

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5 0
3 years ago
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