Answer:
, ](https://tex.z-dn.net/?f=%5B16%20%2B%20%28-18%29%5D%28-4%29)
Step-by-step explanation:
Given: The low temperature on Monday was 16°F. The low temperature on Tuesday was 18°F cooler. The low temperature on Wednesday was –4 times Tuesday’s temperature.
To find: expression that can be used to describe the low temperature on Wednesday
Solution:
Temperature on Monday = 16°F
So,
Temperature on Tuesday = 
Temperature on Wednesday = 
So, expression 
can be used to describe the low temperature on Wednesday.
Also,
\,\,\left \{\because (a-b)=\left [ a+(-b) \right ] \right \}](https://tex.z-dn.net/?f=%2816-18%29%28-4%29%3D%5B16%20%2B%20%28-18%29%5D%28-4%29%5C%2C%5C%2C%5Cleft%20%5C%7B%5Cbecause%20%20%28a-b%29%3D%5Cleft%20%5B%20a%2B%28-b%29%20%5Cright%20%5D%20%5Cright%20%5C%7D)
So, expression also represent temperature on Wednesday.
Answer:
For a continuous random variable X, P(20 ≤ X ≤ 40) = 0.15 and P(X > 40) = 0.16.
Step-by-step explanation:
Here, P(x > 40) = 0.16
a). P(x < 40) = 1 - P(x > 40)
= 1 - 0.16
= 0.84
b). P(x < 20) = 1 - 
= 1 - {P(20 ≤ X ≤ 40) + P(X > 40)}
= 1 - (0.15 + 0.16 )
= 1 - 0.31
= 0. 69
c). P(x = 40) = 0; The probability that a continuous variable assume a particular value is zero.
Since in Jimmy's 90 times die roll six appeared 11 times, so the probability of face of sixes appearing is: 
.
Thus , when the die is rolled 1500 times then it is obvious that the number of times the face of six will appear will also increase proportionately.
This proportionate increase in the number of times the face of six will appear will be given thus:
If six appears 11 times in 90 rolls then to find how many times it will appear in 1500 rolls is calculated as 
where x is the number of times the face of six will appear.
Thus, expression gives:
Therefore, Jimmy can six's approximately 183 times if he rolled the die 1500 times.
The cosine of an angle is the x-coordinate of the point where its terminal ray intersects the unit circle. So, we can draw a line at x=-1/2 and see where it intersects the unit circle. That will tell us possible values of θ/2.
We find that vertical line intersects the unit circle at points where the rays make an angle of ±120° with the positive x-axis. If you consider only positive angles, these angles are 120° = 2π/3 radians, or 240° = 4π/3 radians. Since these are values of θ/2, the corresponding values of θ are double these values.
a) The cosine values repeat every 2π, so the general form of the smallest angle will be
... θ = 2(2π/3 + 2kπ) = 4π/3 + 4kπ
b) Similarly, the values repeat for the larger angle every 2π, so the general form of that is
... θ = 2(4π/3 + 2kπ) = 8π/3 + 4kπ
c) Using these expressions with k=0, 1, 2, we get
... θ = {4π/3, 8π/3, 16π/3, 20π/3, 28π/3, 32π/3}
Answer:
Cost of one doughnut = $1.25
Step-by-step explanation:
Doughnut Cost
3 3.75
1 x
