All categories

2 years ago

What is the range of the function y = StartRoot x + 5 EndRoot?

Mathematics

2 answers:

Aleks [24]2 years ago

8 0

Answer: y≤0

Step-by-step explanation:

Looking at the question, I'm assuming the equation is $y=\sqrt{x+5}$ .

To find the range if this equation, it would be best to know that the graph of a square root looks like. Knowing that x=-5, the graph starts at -5 and then increases slowly to the right. Since there are no restrictions to this equation, the graph goes towards infinity.

Leya [2.2K]2 years ago

4 0

Answer:

b. $y \geq 0$

Step-by-step explanation:

got it right on edg :)

You might be interested in

ABCD is a quadrilateral with A(8,3), B(6, 7), C(-1,5), D(-6, -1). Determine whether ABCD is a trapezoid. Justify

pashok25 [27]

Answer: ABCD is not a trapezoid.

Step-by-step explanation:

6 0

2 years ago

Are of a trapuiezuim

vodomira [7]

Step-by-step explanation:

that is the step by step

brainliest please

7 0

2 years ago

Read 2 more answers

Simply. If the solution is not a real number enter not a real number rotate picture answer all 3 please

yuradex [85]

Answer:

13. $\frac{\sqrt[5]{x^4} }{x}$ .

14. $v = \pm3\sqrt{5}$

15. 2.

Step-by-step explanation:

13. $x^{1/5} * x^{-2/5}$

= $x^{1/5 + (-2/5)}$

= $x^{1/5 - 2/5}$

= $x^{-1/5}$

= $\frac{1}{x^{1/5}}$

= $\frac{x^{4/5}}{x^{1/5 + 4/5}}$

= $\frac{x^{4/5}}{x}$

= $\frac{\sqrt[5]{x^4} }{x}$ .

14. $v^2 - 45 = 0$

$v^2 = 45$

$\sqrt{v^2} = \pm\sqrt{45}$

$\sqrt{v^2} = \pm\sqrt{3^2 * 5}$

$v = \pm3\sqrt{5}$ .

15. $\sqrt[3]{2} * \sqrt[3]{4}$

= $\sqrt[3]{2 * 4}$

= $\sqrt[3]{2 * 2 * 2}$

= $\sqrt[3]{2 ^3}$

= 2.

Hope this helps!

7 0

2 years ago

Please help I don't understand this very well<br>*picture*

Elenna [48]

Answer:

The inequality is 9 less than and equal to 5

The marked area on the line is numbers all below 5 which covers the less than and since it stop directly at 5 it's going to be equal to that as well

8 0

2 years ago

Read 2 more answers

Two equations are given below: a – 3b = 22 a = b – 2 What is the solution to the set of equations in the form (a, b)? (–10, –8)

aliya0001 [1]

Hi Kristian

a - 3b = 22
a = b - 2

We need to solve a = b -2 for a
First, we need to substitute b - 2 for a in a - 3b = 22
a - 3b = 22
b - 2 - 3b = 22
-2b - 2 = 22
-2b = 22 + 2
-2b = 24
b = 24/-2
b = -12

Now substitute -12 for b in a = b - 2
a = b -2
a= -12 - 2
a= -14

Thus, the solution is a = -14 and b = -12

The correct option is the last one (-14,-12)

If you have questions about my answer, please let me know.

Good luck!

4 0

3 years ago