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4 years ago

10

Simplify: 10^1 · 10^3

2 answers:

nevsk [136]4 years ago

8 0

$a^{x} *a^y= a^{x+y}
\\10^1*10^3= 10^4$

Jet001 [13]4 years ago

3 0

$10^1\cdot10^3=10^4$

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lara has a tin of peanuts cashews and pecans she will pick a second nut without looking. how many outcomes are there for her two

KiRa [710]

Possible procedures:

1). peanut, peanut
2). peanut, cashew
3). peanut, pecan
4). cashew, peanut
5). cashew, cashew
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Nine (9) possible procedures.
But ...
(2) and (4) produce the same final result.
(3) and (7) produce the same final result.
(6) and (8) produce the same final result.

So there are only <em><u>six (6)</u></em> possible different outcomes.

6 0

4 years ago

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Hi please help me as soon as possible:

sammy [17]

Answer:

Percentage = 14.2%

Step-by-step explanation:

<u>Given the following data;</u>

Cost of plane ticket = £588

Airport tax = $130

£1 = $1.34

To find the percentage of the total cost spent on airport tax;

First of all, we would convert the ticket cost in pounds (£) to dollars ($).

Cost of plane ticket = £588 to $ = 588 * 1.34 = $787. 92

Total cost = Cost of plane ticket + Airport tax

Total cost = 787. 92 + 130

Total cost = $917.92

$Percentage \; cost = \frac {130}{917.92} * 100$

$Percentage = 0.1416 * 100$

<em>Percentage cost = 14.16 to 1 d.p = 14.2%</em>

<em>Therefore, the percentage of the total cost spent on airport tax by Rimo is 14.2 percent. </em>

6 0

3 years ago

Which solution from the equations below results in an irrational number?

Tanya [424]

Answer:

Step-by-step explanation:

4 0

3 years ago

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Simplify : (√x + √y ) (√x − √y) (x + y)(x2 + y2)

Ivan

$Solution, \mathrm{Expand}\::\left(\sqrt{x}+\sqrt{y}\right)\left(\sqrt{x}-\sqrt{y}\right)\left(x+y\right)\left(x^2+y^2\right):\quad :x^4-:y^4$

$Steps:$

$\mathrm{Expand}\:\left(\sqrt{x}+\sqrt{y}\right)\left(\sqrt{x}-\sqrt{y}\right):\quad x-y, =\left(x-y\right)\left(x+y\right)\left(x^2+y^2\right)$

$\mathrm{Expand}\:\left(x-y\right)\left(x+y\right):\quad x^2-y^2, =:\left(x^2-y^2\right)\left(x^2+y^2\right)$

$\mathrm{Expand}\:\left(x^2-y^2\right)\left(x^2+y^2\right):\quad x^4-y^4, =:\left(x^4-y^4\right)$

$\mathrm{Expand}\::\left(x^4-y^4\right):\quad :x^4-:y^4, =:x^4-:y^4$

The correct answer is <u><em> $x^4-y^4$ </em></u>

Hope this helps!!!

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3 years ago

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AURORKA [14]

It would be 45% your welcome

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3 years ago